Applied Mechanics and Graphic Statics The angle which an inclined surface makes with the horizontal when a body placed on it is on the point of moving down, is called Angle of inclination None of these Angle of repose Angle of friction Angle of inclination None of these Angle of repose Angle of friction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angle of friction is: The force of friction when the body is in motion The ratio of the friction and the normal reaction The angle between the normal reaction and the resultant of normal reaction and limiting friction The force of friction at which the body is just about to move The force of friction when the body is in motion The ratio of the friction and the normal reaction The angle between the normal reaction and the resultant of normal reaction and limiting friction The force of friction at which the body is just about to move ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone of mass 1 kg is tied to a string of length 1 m and whirled in a horizontal circle at a constant angular speed 5 rad/sec. The tension in the string is, 10 N 25 N 15 N 5 N 10 N 25 N 15 N 5 N ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The motion of a particle is described by the relation x = t²- 10t + 30, where x is in meters and t in seconds. The total distance travelled by the particle from t = 0 to t = 10 seconds would be 50 m Zero 30 m 60 m 50 m Zero 30 m 60 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A string of length 90 cm is fastened to two points ‘A’ and ‘B’ at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force ‘P’ is applied to the ring such that it is in equilibrium vertically below ‘B’. The value of ‘P’ is: 60 g 80 g 100 g 40 g 60 g 80 g 100 g 40 g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 2gh v = √(2gh) v = 1/√(2gh) v = 2gh² v = 2gh v = √(2gh) v = 1/√(2gh) v = 2gh² ANSWER DOWNLOAD EXAMIANS APP