RCC Structures Design The allowable tensile stress in mild steel stirrups, reinforced cement concrete, is 1400 kg/cm² 190 kg/cm² 230 kg/cm² 260 kg/cm² 1400 kg/cm² 190 kg/cm² 230 kg/cm² 260 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A short column 20 cm × 20 cm in section is reinforced with 4 bars whose area of cross section is 20 sq. cm. If permissible compressive stresses in concrete and steel are 40 kg/cm² and 300 kg/cm², the Safe load on the column, should not exceed 412,000 kg 4,120 kg 41,200 kg None of these 412,000 kg 4,120 kg 41,200 kg None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is Kx (1 + x/l) + bw All listed here Kx (1 - x/l) + bw K/x (1 + x/d) + bw Kx (1 + x/l) + bw All listed here Kx (1 - x/l) + bw K/x (1 + x/d) + bw ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The steel generally used in R.C.C. work, is High tension steel Stainless Mild steel High carbon steel High tension steel Stainless Mild steel High carbon steel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If R and T are rise and tread of a stair spanning horizontally, the steps are supported by a wall on one side and by a stringer beam on the other side, the steps are designed as beams of width R + T R - T √(R² + T²) T - R R + T R - T √(R² + T²) T - R ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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