Theory of Structures Shear strain energy theory for the failure of a material at elastic limit, is due to Von Mises Rankine Guest or Trecas St. Venant Von Mises Rankine Guest or Trecas St. Venant ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the length and diameter of a simply supported uniform circular beam which experiences maximum bending stress equal to tensile stress due to same load at its mid span, is 1/4 1/8 1/3 1/2 1/4 1/8 1/3 1/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A shaft subjected to a bending moment M and a torque T, experiences Maximum shear stress = 16 T/πd³ Maximum bending stress = 32M/πd³ Both A and B Neither A nor B Maximum shear stress = 16 T/πd³ Maximum bending stress = 32M/πd³ Both A and B Neither A nor B ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) All of these E = 2N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The horizontal thrust on the ends of a two hinged semicircular arch of radius ‘R’ carrying All of these A uniformly distributed load ? per unit run over its right half span, is ? ?R/? A distributed load varying from zero at the left end to ? per unit horizontal run at the right end, is ? ?R/? A uniformly distributed load ? per unit run over its entire span is 4/3 ?R/? All of these A uniformly distributed load ? per unit run over its right half span, is ? ?R/? A distributed load varying from zero at the left end to ? per unit horizontal run at the right end, is ? ?R/? A uniformly distributed load ? per unit run over its entire span is 4/3 ?R/? ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then M/I = E/R = Y/F I/M = R/E = F/Y M/I = E/R = F/Y M/I = R/E = F/Y M/I = E/R = Y/F I/M = R/E = F/Y M/I = E/R = F/Y M/I = R/E = F/Y ANSWER DOWNLOAD EXAMIANS APP
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