Applied Mechanics and Graphic Statics Rate of change of angular momentum is equal to Force Linear momentum Torque Impulse Force Linear momentum Torque Impulse ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘ω’ rad/sec is the angular velocity of a crank whose radius is ‘r’. If it makes θ° with inner dead centre and obliquity of the connecting rod ‘l’ is ‘ϕ’, the velocity v of the piston, is given by the equation ω² (l sin ϕ + r cos φ tan θ) ω² (l cos ϕ + r sin ϕ tan θ) ω (l sin ϕ + r cos ϕ tan θ) ω² (l sin ϕ - r cos θ tan ϕ) ω² (l sin ϕ + r cos φ tan θ) ω² (l cos ϕ + r sin ϕ tan θ) ω (l sin ϕ + r cos ϕ tan θ) ω² (l sin ϕ - r cos θ tan ϕ) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone was thrown vertically upwards from the ground with a velocity of 50 m/sec. After 5 seconds another stone was thrown vertically upwards from the same place. If both the stones strike the ground at the same time, then the velocity with which the second stone was thrown should be (Assume g = 10 m/sec²) 25 m/sec 50 m/sec 40 m/sec 15 m/sec 25 m/sec 50 m/sec 40 m/sec 15 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A flywheel of moment of inertia 20 kg.m is acted upon by a tangential force of 5 N at 2 m from its axis, for 3 seconds. The increase in angular velocity in radian per second is 3 2 43892 43832 3 2 43892 43832 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals P sin θ/P + Q tan θ Q sin θ/P + Q cos θ P sin θ/P - Q cos θ Q sin θ/P + Q sin θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ P sin θ/P - Q cos θ Q sin θ/P + Q sin θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When two forces, each equal to P, act at 90° to each other, then the resultant will be 2P P√2 P P/√2 2P P√2 P P/√2 ANSWER DOWNLOAD EXAMIANS APP
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