Applied Mechanics and Graphic Statics Equation of motion of a point in a straight line, is 2fS = v² - u² S = ut + ½ ft² All listed here v = u + ft 2fS = v² - u² S = ut + ½ ft² All listed here v = u + ft ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If ‘α’ is the angular acceleration of a compound pendulum whose angular displacement is ‘θ’, the frequency of the motion is 2π √(α/θ) (1/2π) √(α/θ) 4π √(α/θ) 2π √(α - θ) 2π √(α/θ) (1/2π) √(α/θ) 4π √(α/θ) 2π √(α - θ) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘ω’ rad/sec is the angular velocity of a crank whose radius is ‘r’. If it makes θ° with inner dead centre and obliquity of the connecting rod ‘l’ is ‘ϕ’, the velocity v of the piston, is given by the equation ω² (l sin ϕ + r cos φ tan θ) ω² (l cos ϕ + r sin ϕ tan θ) ω (l sin ϕ + r cos ϕ tan θ) ω² (l sin ϕ - r cos θ tan ϕ) ω² (l sin ϕ + r cos φ tan θ) ω² (l cos ϕ + r sin ϕ tan θ) ω (l sin ϕ + r cos ϕ tan θ) ω² (l sin ϕ - r cos θ tan ϕ) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A circular disc rotates at n rpm. The angular velocity of a circular ring of same mass and radius as the disc and to have the same angular momentum is n/2 rpm n rpm n/4 rpm 2n rpm n/2 rpm n rpm n/4 rpm 2n rpm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angle of projection at which the horizontal range and maximum height of a projectile are equal to 56° 36° 45° 76° 56° 36° 45° 76° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The shape of a suspended cable under its own weight, is Parabolic Catenary Elliptical Circular Parabolic Catenary Elliptical Circular ANSWER DOWNLOAD EXAMIANS APP
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