If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (c - a)/4 M = pb (b + a)/8 M = pb (b - a)²/4 M = pb (b + a)/8 M = pb (b - a)²/8 TRUE ANSWER : ? YOUR ANSWER : ?
The live load to be considered for an inaccessible roof, is 200 kg/m² 150 kg/cm² 75 kg/m² Nil TRUE ANSWER : ? YOUR ANSWER : ?
If diameter of a reinforcement bar is d, the anchorage value of the hook is 4d 8d 12d 16d TRUE ANSWER : ? YOUR ANSWER : ?
Minimum spacing between horizontal parallel reinforcement of the same size should not be less than 3.5 diameters One diameter 2.5 diameters 3 diameters TRUE ANSWER : ? YOUR ANSWER : ?
In case the factor of safety against sliding is less than 1.5, a portion of slab is constructed downwards at the end of the heel slab, which is known as A cut-off wall A rib All listed here A key TRUE ANSWER : ? YOUR ANSWER : ?
The load stress of a section can be reduced by Replacing smaller bars by greater number of greater bars Increasing the total perimeter of bars Decreasing the lever arm Replacing larger bars by greater number of small bars TRUE ANSWER : ? YOUR ANSWER : ?
The maximum ratio of span to depth of a cantilever slab, is 12 10 16 8 TRUE ANSWER : ? YOUR ANSWER : ?
If R and T are rise and tread of a stair spanning horizontally, the steps are supported by a wall on one side and by a stringer beam on the other side, the steps are designed as beams of width R + T T - R R - T √(R² + T²) TRUE ANSWER : ? YOUR ANSWER : ?
If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is Kx (1 - x/l) + bw All listed here K/x (1 + x/d) + bw Kx (1 + x/l) + bw TRUE ANSWER : ? YOUR ANSWER : ?
If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) TRUE ANSWER : ? YOUR ANSWER : ?