A 470 resistor and a 0.2 F capacitor are in parallel across a 2.5 kHz ac source. The admittance, Y, in rectangular form, is 318.3 2.12 mS + j3.14 mS 3.14 mS + j2.12 mS 212 TRUE ANSWER : ? YOUR ANSWER : ?
A 47Ω resistor and a capacitor with 150Ω of capacitive reactance are in series across an ac source. The impedance, expressed in rectangular form, is Z = 47Ω – j150Ω Z = 47Ω + j150Ω Z = 197Ω Z = 103Ω TRUE ANSWER : ? YOUR ANSWER : ?
A capacitor with 150Ω of capacitive reactance is across an ac source. The impedance, expressed in polar form, is Z = 150 angle 180° Ω Z = 150 angle – 90° Ω Z = 150 Z = 150 –90° Ω TRUE ANSWER : ? YOUR ANSWER : ?
When the frequency of the voltage applied to a series RC circuit is decreased, the impedance doubles remains the same decreases increases TRUE ANSWER : ? YOUR ANSWER : ?
In a series RC circuit, 12 V(rms) is measured across the resistor and 15 V(rms) is measured across the capacitor. The rms source voltage is 19.2 V 3 V 27 V 1.9 V TRUE ANSWER : ? YOUR ANSWER : ?
An ac circuit consists of a resistor and a capacitor. To increase the phase angle above 45°, the following condition must exist: R < XC R > XC R = XC R = 5XC TRUE ANSWER : ? YOUR ANSWER : ?
A 12 kΩ resistor is in series with a 0.02 μF capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.3 angle 0° mA, what is the source voltage expressed in polar form? 4.11 V 45.6 V 411.3 V 0.411 V TRUE ANSWER : ? YOUR ANSWER : ?
The voltages in Problem 4 are measured at a certain frequency. To make the capacitor voltage greater than the resistor voltage, the frequency must be decreased is held constant must be increased has no effect TRUE ANSWER : ? YOUR ANSWER : ?
A 6 kHz sinusoidal voltage is applied to a series RC circuit. The frequency of the voltage across the resistor is 12 kHz 18 kHz 0 Hz 6 kHz TRUE ANSWER : ? YOUR ANSWER : ?
In a series RC circuit, when the frequency and the resistance are halved, the impedance is reduced to one-fourth is halved cannot be determined without values doubles TRUE ANSWER : ? YOUR ANSWER : ?