A 120Ω resistor is in parallel with a capacitor with a capacitive reactance of 40 Ω. Both components are across a 12 V ac source. What is the magnitude of the total impedance? 37.9Ω 3.7Ω 14400Ω 4800Ω TRUE ANSWER : ? YOUR ANSWER : ?
A 12 kΩ resistor is in series with a 0.02 μF capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.3 angle 0° mA, what is the source voltage expressed in polar form? 411.3 V 4.11 V 45.6 V 0.411 V TRUE ANSWER : ? YOUR ANSWER : ?
The complex number 6 + j6 is equivalent to 3645° 8.4890° 645° 8.4845° TRUE ANSWER : ? YOUR ANSWER : ?
A 47Ω resistor and a capacitor with a capacitive reactance of 120 are in series across an ac source. What is the circuit impedance, Z? 73Ω 167Ω 12.9Ω 129Ω TRUE ANSWER : ? YOUR ANSWER : ?
Point +4 on the complex plane is 4 units below the origin on the j axis 4 units left of the origin on the real axis 4 units above the origin on the j axis 4 units right of the origin on the real axis TRUE ANSWER : ? YOUR ANSWER : ?
What is the angular difference between +j4 and –j4? 270° 90° 30° 180° TRUE ANSWER : ? YOUR ANSWER : ?
A 2 k resistor is in series with a 0.015 F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle? 707 and θ = –19.5° 734 and θ = –38.9° 73.4 and θ = –19.5° 2121 and θ = –19.5° TRUE ANSWER : ? YOUR ANSWER : ?
A 47Ω resistor and a capacitor with 150Ω of capacitive reactance are in series across an ac source. The impedance, expressed in rectangular form, is Z = 47Ω + j150Ω Z = 103Ω Z = 47Ω – j150Ω Z = 197Ω TRUE ANSWER : ? YOUR ANSWER : ?
The voltages in Problem 4 are measured at a certain frequency. To make the capacitor voltage greater than the resistor voltage, the frequency is held constant must be increased must be decreased has no effect TRUE ANSWER : ? YOUR ANSWER : ?
A capacitor with 150Ω of capacitive reactance is across an ac source. The impedance, expressed in polar form, is Z = 150 Z = 150 angle – 90° Ω Z = 150 angle 180° Ω Z = 150 –90° Ω TRUE ANSWER : ? YOUR ANSWER : ?