A capacitor with 150Ω of capacitive reactance is across an ac source. The impedance, expressed in polar form, is Z = 150 Z = 150 –90° Ω Z = 150 angle – 90° Ω Z = 150 angle 180° Ω TRUE ANSWER : ? YOUR ANSWER : ?
In the complex plane, the number 14 – j5 is located in the second quadrant first quadrant fourth quadrant third quadrant TRUE ANSWER : ? YOUR ANSWER : ?
An ac circuit consists of a resistor and a capacitor. To increase the phase angle above 45°, the following condition must exist: R > XC R = 5XC R = XC R < XC TRUE ANSWER : ? YOUR ANSWER : ?
The voltages in Problem 4 are measured at a certain frequency. To make the capacitor voltage greater than the resistor voltage, the frequency is held constant must be decreased has no effect must be increased TRUE ANSWER : ? YOUR ANSWER : ?
What is the angular difference between +j4 and –j4? 90° 180° 270° 30° TRUE ANSWER : ? YOUR ANSWER : ?
A 2 k resistor is in series with a 0.015 F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle? 734 and θ = –38.9° 2121 and θ = –19.5° 707 and θ = –19.5° 73.4 and θ = –19.5° TRUE ANSWER : ? YOUR ANSWER : ?
In a series RC circuit, when the frequency and the resistance are halved, the impedance cannot be determined without values doubles is reduced to one-fourth is halved TRUE ANSWER : ? YOUR ANSWER : ?
A 47Ω resistor and a capacitor with 150Ω of capacitive reactance are in series across an ac source. The impedance, expressed in rectangular form, is Z = 47Ω + j150Ω Z = 47Ω – j150Ω Z = 103Ω Z = 197Ω TRUE ANSWER : ? YOUR ANSWER : ?
A positive angle of 30° is equivalent to a negative angle of –330° –30° –180° –60° TRUE ANSWER : ? YOUR ANSWER : ?
A 47Ω resistor and a capacitor with a capacitive reactance of 120 are in series across an ac source. What is the circuit impedance, Z? 167Ω 73Ω 129Ω 12.9Ω TRUE ANSWER : ? YOUR ANSWER : ?