A 2 k resistor is in series with a 0.015 F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle? 2121 and θ = –19.5° 734 and θ = –38.9° 73.4 and θ = –19.5° 707 and θ = –19.5° TRUE ANSWER : ? YOUR ANSWER : ?
A capacitor with 150Ω of capacitive reactance is across an ac source. The impedance, expressed in polar form, is Z = 150 –90° Ω Z = 150 angle – 90° Ω Z = 150 angle 180° Ω Z = 150 TRUE ANSWER : ? YOUR ANSWER : ?
A resistor and a capacitor are in series across a 20 V ac source. Circuit impedance is 4.33 k. Current flow in the circuit is 9.2 mA 4.6 mA 460 mA 92 mA TRUE ANSWER : ? YOUR ANSWER : ?
A 470 resistor and a 0.2 F capacitor are in parallel across a 2.5 kHz ac source. The admittance, Y, in rectangular form, is 318.3 3.14 mS + j2.12 mS 2.12 mS + j3.14 mS 212 TRUE ANSWER : ? YOUR ANSWER : ?
A 2 kΩ resistor and a 0.002 μF capacitor are in series across an ac source. Current in the circuit is 6.50 mA. The true power is 130 mW 845 mW 13 mW 84.5 mW TRUE ANSWER : ? YOUR ANSWER : ?
A 6 kHz sinusoidal voltage is applied to a series RC circuit. The frequency of the voltage across the resistor is 6 kHz 12 kHz 18 kHz 0 Hz TRUE ANSWER : ? YOUR ANSWER : ?
The voltages in Problem 4 are measured at a certain frequency. To make the capacitor voltage greater than the resistor voltage, the frequency is held constant must be decreased has no effect must be increased TRUE ANSWER : ? YOUR ANSWER : ?
A 12 kΩ resistor is in series with a 0.02 μF capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.3 angle 0° mA, what is the source voltage expressed in polar form? 411.3 V 4.11 V 45.6 V 0.411 V TRUE ANSWER : ? YOUR ANSWER : ?
For a certain load, the true power is 150 W and the reactive power is 125 VAR. The apparent power is 25 W 275 W 19.52 W 195.2 W TRUE ANSWER : ? YOUR ANSWER : ?
In a series RC circuit, 12 V(rms) is measured across the resistor and 15 V(rms) is measured across the capacitor. The rms source voltage is 1.9 V 27 V 3 V 19.2 V TRUE ANSWER : ? YOUR ANSWER : ?