When the frequency of the voltage applied to a series RC circuit is decreased, the impedance decreases increases doubles remains the same TRUE ANSWER : ? YOUR ANSWER : ?
A 47Ω resistor and a capacitor with 150Ω of capacitive reactance are in series across an ac source. The impedance, expressed in rectangular form, is Z = 197Ω Z = 47Ω + j150Ω Z = 103Ω Z = 47Ω – j150Ω TRUE ANSWER : ? YOUR ANSWER : ?
In a series RC circuit, 12 V(rms) is measured across the resistor and 15 V(rms) is measured across the capacitor. The rms source voltage is 3 V 19.2 V 27 V 1.9 V TRUE ANSWER : ? YOUR ANSWER : ?
In a series RC circuit, when the frequency and the resistance are halved, the impedance is reduced to one-fourth doubles is halved cannot be determined without values TRUE ANSWER : ? YOUR ANSWER : ?
In a parallel RC circuit, there is 100 mA through the resistive branch and 100 mA through the capacitive branch. The total rms current is 100 mA 282 mA 200 mA 141 mA TRUE ANSWER : ? YOUR ANSWER : ?
The complex number 40 angle 55° is equivalent to 40 + j40 55 + j55 45.88 + j65.52 22.94 + j32.76 TRUE ANSWER : ? YOUR ANSWER : ?
A 12 kΩ resistor is in series with a 0.02 μF capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.3 angle 0° mA, what is the source voltage expressed in polar form? 45.6 V 411.3 V 4.11 V 0.411 V TRUE ANSWER : ? YOUR ANSWER : ?
What is the angular difference between +j4 and –j4? 30° 180° 90° 270° TRUE ANSWER : ? YOUR ANSWER : ?
When the frequency of the voltage applied to a series RC circuit is increased, the phase angle increases becomes erratic decreases remains the same TRUE ANSWER : ? YOUR ANSWER : ?
A capacitor with 150Ω of capacitive reactance is across an ac source. The impedance, expressed in polar form, is Z = 150 angle 180° Ω Z = 150 angle – 90° Ω Z = 150 –90° Ω Z = 150 TRUE ANSWER : ? YOUR ANSWER : ?