What happen in case of multiple catch blocks? None of these Either super or subclass can be caught first. The superclass exception must be caught first. The superclass exception cannot caught first. TRUE ANSWER : ? YOUR ANSWER : ?
Which keyword is used to specify the exception thrown by method? throws catch finally throw TRUE ANSWER : ? YOUR ANSWER : ?
Given the following piece of code:class SalaryCalculationException extends Exception{}class Person{ public void calculateSalary() throws SalaryCalculationException{ //... throw new SalaryCalculationException(); //... }}class Company{ public void paySalaries(){ new Person().calculateSalary(); }}Which of the following statements is correct?1. This code will compile without any problems.2. This code will compile if in method paySalaries() we return a boolean in stead of void.3. This code will compile if we add a try-catch block in paySalaries().4. This code will compile if we add throws SalaryCalculationException in the signature of method paySalaries(). 3 and 4 1 and 4 2 and 4 1 and 2 2 and 3 TRUE ANSWER : ? YOUR ANSWER : ?
Which keyword is used to explicitly throw an exception? try catch throwing throw TRUE ANSWER : ? YOUR ANSWER : ?
What is the output of the following program code?public class Test{ public static void main(String args[]){ try{ int i; return; } catch(Exception e){ System.out.print("inCatchBlock"); } finally{ System.out.println("inFinallyBlock"); } }} inCatchBlock inFinallyBlock The program will return without printing anything inCatchBlock inFinallyBlock TRUE ANSWER : ? YOUR ANSWER : ?
The class at the top of exception class hierarchy is ................. Object Throwable ArithmeticException Exception TRUE ANSWER : ? YOUR ANSWER : ?
Which exception is thrown when an array element is accessed beyond the array size? ArrayIndexOutOfBoundsException ArrayIndexOutOfBounds None of these ArrayElementOutOfBounds TRUE ANSWER : ? YOUR ANSWER : ?
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }} "null pointer exception" is printed. "exception" is printed. "one" is printed. None of these Compilation fails saying NullPointerException has already been caught. TRUE ANSWER : ? YOUR ANSWER : ?
What is the output for the below code ?import java.io.FileNotFoundException;class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); }}class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); }}public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); }} printName() None of these Compilation succeed but no output Value-A Name-B Compilation fails-Exception NullPointerException is not compatible with throws clause in TRUE ANSWER : ? YOUR ANSWER : ?
What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }} Prints out: Finally Compile with error Prints out: Exception Finally Prints out: Exception None of these TRUE ANSWER : ? YOUR ANSWER : ?