The finalize() method is called just prior to Before garbage collection. An object or variable goes out of scope. None of these An object, variable or method goes out of scope. A variable goes out of scope. TRUE ANSWER : ? YOUR ANSWER : ?
The implicit return type of a constructor is void None of these There is no return type. A class object in which it is defined. TRUE ANSWER : ? YOUR ANSWER : ?
Which of these is a legal definition of a method named examveda assuming it throws IOException, and returns void. Also assume that the method does not take any arguments. Select the one correct answer. void examians() throw IOException{} void examians(void) throws IOException{} examians() throws IOException{} void examians() throws IOException{} void examians() {} throws IOException TRUE ANSWER : ? YOUR ANSWER : ?
The main method should be static for the reason It can be accessed easily by the class loader. None of these It can be accessed by every method or variable without any hindrance. It can be executed without creating any instance of the class. TRUE ANSWER : ? YOUR ANSWER : ?
What is the output of the program?class Test{ public int display(int x, int y){ return ("The sum of x and y is " + x + y); } public static void main(String args[]){ Test test = new Test(); System.out.println(test.display(4,5)); } } None of these does not compile The sum of x and y is 9 The sum of x and y is 45 TRUE ANSWER : ? YOUR ANSWER : ?
What is the expected output?public class Profile { private Profile(int w) { // line 1 System.out.print(w); } public static Profile() { // line 5 System.out.print (10); } public static void main(String args[]) { Profile obj = new Profile(50); }} Won't compile because of line (5), constructor can't be static Won't compile because of line (1), constructor can't be private 50 10 50 TRUE ANSWER : ? YOUR ANSWER : ?
class MyClass{int i;int j;public MyClass(int i, int j){this.i = i;this.j = j;}public void call(){System.out.print("One");}}public class Test{public static void main(String args[]){MyClass m = new MyClass(); //line 1m.call(); //line 2}} Compilation fails due to an error on line 2 One Compilation succeed but no output. Compilation fails due to an error on line 1 TRUE ANSWER : ? YOUR ANSWER : ?
Determine Output:class A{public static void method(int i){System.out.print("Method 1");}public static int method(String str){System.out.print("Method 2");return 0;}}public class Test{ public static void main(String args[]){A.method(5);}} Method 1 Method 2 None of these Compile time error as final method can't be overloaded TRUE ANSWER : ? YOUR ANSWER : ?
What is the expected output?public class Profile {private Profile(int w) { // line 1System.out.print(w);}public final Profile() { // line 5System.out.print(10);}public static void main(String args[]) {Profile obj = new Profile(50);}} 10 50 50 Won't compile because of line (1); constructor can't be private Won't compile because of line (5); constructor can't be final TRUE ANSWER : ? YOUR ANSWER : ?
In which area of memory, the system stores parameters and local variables whenever a method is invoked? Heap Array Storage Area Stack TRUE ANSWER : ? YOUR ANSWER : ?