What is the output for the below code ?1. public class A{2. int add(int i, int j){3. return i+j;4. }5. }6. public class B extends A{7. public static void main(String argv[]){8. short s = 9;9. System.out.println(add(s,6));10. }11.} Compile fail due to error on line no 2 None of these Compile fail due to error on line no 9 15 Compile fail due to error on line no 8 TRUE ANSWER : ? YOUR ANSWER : ?
Which of the following statements regarding static methods are correct?1. Static methods are difficult to maintain, because you can not change their implementation.2. Static methods can be called using an object reference to an object of the class in which this method is defined.3. Static methods are always public, because they are defined at class-level.4. Static methods do not have direct access to non-static methods which are defined inside the same class. 1 and 3 2 and 4 1 and 2 3 and 4 TRUE ANSWER : ? YOUR ANSWER : ?
Determine output:public class Test{ public static void main(String args[]){ MyClass obj = new MyClass(); obj.val = 1; obj.call(obj); System.out.println(obj.val); }}class MyClass{ public int val; public void call(MyClass ref){ ref.val++; }} 3 2 1 Compilation Error None of these TRUE ANSWER : ? YOUR ANSWER : ?
public class MyClass{ }For the above class(MyClass) what is the correct way of declaring constructor? public MyClass(){} public MyClass(void){} MyClass(void) {} 1 and 3 MyClass(){} TRUE ANSWER : ? YOUR ANSWER : ?
The main method should be static for the reason It can be accessed easily by the class loader. It can be executed without creating any instance of the class. It can be accessed by every method or variable without any hindrance. None of these TRUE ANSWER : ? YOUR ANSWER : ?
What is the expected output?public class Profile {private Profile(int w) { // line 1System.out.print(w);}public final Profile() { // line 5System.out.print(10);}public static void main(String args[]) {Profile obj = new Profile(50);}} Won't compile because of line (1); constructor can't be private 10 50 50 Won't compile because of line (5); constructor can't be final TRUE ANSWER : ? YOUR ANSWER : ?
What is the expected output?class Animal {Animal() {System.out.println("Animal");}}class Wild extends Animal{Wild() {System.out.println("Wild");super();}}public class Test {public static void main(String args[]) {Wild wild = new Wild();}} Compilation Error Wild Animal Animal Wild Runtime Exception TRUE ANSWER : ? YOUR ANSWER : ?
class MyClass{int i;int j;public MyClass(int i, int j){this.i = i;this.j = j;}public void call(){System.out.print("One");}}public class Test{public static void main(String args[]){MyClass m = new MyClass(); //line 1m.call(); //line 2}} Compilation succeed but no output. Compilation fails due to an error on line 2 One Compilation fails due to an error on line 1 TRUE ANSWER : ? YOUR ANSWER : ?
public class Test { }What is the prototype of the default constructor? public Test( ) Test( ) Test(void) public Test(void) None of these TRUE ANSWER : ? YOUR ANSWER : ?
Given the following piece of code:class Person{ public int number;}public class Test{ public void doIt(int i , Person p){ i = 5; p.number = 8; } public static void main(String args[]){ int x = 0; Person p = new Person(); new Test().doIt(x, p); System.out.println(x + " " + p.number); }}What is the result? 5 8 0 8 0 0 5 0 TRUE ANSWER : ? YOUR ANSWER : ?