Which of the following options is the best for generating random integer 0 or 1? (int)(Math.random() + 0.5) (int)Math.random() + 1 (int)Math.random() (int)(Math.random() + 0.2) TRUE ANSWER : ? YOUR ANSWER : ?
What will be the result of compiling and running the given code?class A{ int b=10; private A(){ this.b=7; } int f(){ return b; }}class B extends A{ int b;}public class Test{ public static void main(String[] args){ A a = new B(); System.out.println(a.f()); }} Compilation Fails None of these Prints 10 Prints 0 Prints 7 TRUE ANSWER : ? YOUR ANSWER : ?
Which of the following statements regarding static methods are correct?1. Static methods are difficult to maintain, because you can not change their implementation.2. Static methods can be called using an object reference to an object of the class in which this method is defined.3. Static methods are always public, because they are defined at class-level.4. Static methods do not have direct access to non-static methods which are defined inside the same class. 1 and 2 1 and 3 2 and 4 3 and 4 TRUE ANSWER : ? YOUR ANSWER : ?
public class Test { }What is the prototype of the default constructor? public Test(void) Test( ) public Test( ) None of these Test(void) TRUE ANSWER : ? YOUR ANSWER : ?
What is the output of the program?class Test{ public int display(int x, int y){ return ("The sum of x and y is " + x + y); } public static void main(String args[]){ Test test = new Test(); System.out.println(test.display(4,5)); } } does not compile None of these The sum of x and y is 9 The sum of x and y is 45 TRUE ANSWER : ? YOUR ANSWER : ?
The finalize() method is called just prior to An object or variable goes out of scope. A variable goes out of scope. None of these Before garbage collection. An object, variable or method goes out of scope. TRUE ANSWER : ? YOUR ANSWER : ?
class MyClass{int i;int j;public MyClass(int i, int j){this.i = i;this.j = j;}public void call(){System.out.print("One");}}public class Test{public static void main(String args[]){MyClass m = new MyClass(); //line 1m.call(); //line 2}} One Compilation fails due to an error on line 1 Compilation succeed but no output. Compilation fails due to an error on line 2 TRUE ANSWER : ? YOUR ANSWER : ?
What is the output for the below code?public class Test{ public static void printValue(int i, int j, int k){ System.out.println("int"); } public static void printValue(byte...b){ System.out.println("long"); } public static void main(String... args){ byte b = 9; printValue(b,b,b); }} Compilation clean but throws RuntimeException None of these int Compilation fails long TRUE ANSWER : ? YOUR ANSWER : ?
The main method should be static for the reason None of these It can be accessed easily by the class loader. It can be accessed by every method or variable without any hindrance. It can be executed without creating any instance of the class. TRUE ANSWER : ? YOUR ANSWER : ?