The law of the machine is (where P = Effort applied to lift the load, m = A constant which is equal to the slope of the line, W = Load lifted, and C = Another constant which represents the machine friction.) P = mW - C P = m/W + C P = C - mW P = mW + C TRUE ANSWER : ? YOUR ANSWER : ?
If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion, P/m.a = 0 P + m.a = 0 P - m.a = 0 P × m.a = 0 TRUE ANSWER : ? YOUR ANSWER : ?
The range of projectile (R) on an upward inclined plane is g. cos² β/2u². sin (α + β). cos α g. cos² β/2u². sin (α - β). cos α 2u². sin (α - β). cos α/g. cos² β 2u². sin (α + β). cos α/g. cos² β TRUE ANSWER : ? YOUR ANSWER : ?
The maximum frictional force which comes into play when a body just begins to slide over another surface is called Kinematic friction Limiting friction Sliding friction Rolling friction TRUE ANSWER : ? YOUR ANSWER : ?
The maximum acceleration of a particle moving with simple harmonic motion is ωr ω²r ω ω/r TRUE ANSWER : ? YOUR ANSWER : ?
The coefficient of friction depends upon Shape of the surfaces All of these Area of contact Nature of surfaces TRUE ANSWER : ? YOUR ANSWER : ?
The centre of percussion of the homogeneous rod of length ‘L’ suspended at the top will be 2L/3 L/2 3L/4 L/3 TRUE ANSWER : ? YOUR ANSWER : ?
A body of weight 'W' is required to move up on rough inclined plane whose angle of inclination with the horizontal is 'α'. The effort applied parallel to the plane is given by (where μ = tanφ = Coefficient of friction between the plane and the body.) P = W (sinα + μcosα) P = W tanα P = W tan (α + φ) P = W (cosα + μsinα) TRUE ANSWER : ? YOUR ANSWER : ?
The acceleration of a body sliding down an inclined surface is None of these g cosθ g tanθ g sinθ TRUE ANSWER : ? YOUR ANSWER : ?