In the time-cost optimisation, using CPM method for network analysis, the crashing of the activities along the critical path is done starting with the activity having Least cost slope Shortest duration Highest cost slope Longest duration TRUE ANSWER : ? YOUR ANSWER : ?
In time-cost optimization of a project, crashing is done. On all the activities On original critical activities and those that become critical at any stage of crashing in the order of ascending cost slope Only on activities lying on the original critical path and having flatter cost slopes On all the activities lying on the critical path TRUE ANSWER : ? YOUR ANSWER : ?
For a given activity, the optimistic time, pessimistic time and the most probable estimates are 5, 17 and 8 days respectively, The expected time is 15 days 10 days 8 days 9 days TRUE ANSWER : ? YOUR ANSWER : ?
For the execution of a project, a contractor is A firm An agency All listed here A person TRUE ANSWER : ? YOUR ANSWER : ?
Mobilization advance up to 10% of the cost of work is given to a contractor For all activities required to start the work at site on finalization of the contract document For the purchase of construction materials For the payment of advances to labour and other staff On commencement of work at site for payment of loan taken by him TRUE ANSWER : ? YOUR ANSWER : ?
Wheeled tractors are replacing crawler tractors because1. Wheeled tractors travel faster.2. Crawler tractors are more expensive.3. Track parts of a crawler wear out quickly.4. Crawler tractors have stick control.of following statements 2, 3 and 4 are correct 1, 3 and 4 are correct 1, 2 and 4 are correct 1, 2 and 3 are correct TRUE ANSWER : ? YOUR ANSWER : ?
A CPM family includes All listed here CPA (Critical Path Analysis) CPP (Critical Path Plotted) MCE (Minimum Cost Expenditure) TRUE ANSWER : ? YOUR ANSWER : ?
Rolling resistance of a wheel depends upon<br/>(i) Vehicle load<br/>(ii) Grade<br/>(iii) Ground conditions (i) and (ii) are correct Only (i) is correct (i) and (iii) are correct (ii) and (iii) are correct TRUE ANSWER : ? YOUR ANSWER : ?
If D is the duration, ES and EF are the earliest start and finish, LS and LF are latest start and latest finish time, then the following relation holds good LF = LS + D All listed here EF = ES + D LS = LF - D TRUE ANSWER : ? YOUR ANSWER : ?
If a is the optimistic time, b is the pessimistic time and m is most likely time of an activity, the expected time of the activity, is (a + m + b)/6 (a + 4m + b)/6 (a + 2m + b)/6 (a + 5m + b)/6 TRUE ANSWER : ? YOUR ANSWER : ?