Applied Mechanics and Graphic Statics Power developed by a torque, is All listed here 2πNT /60 watts 2πNT/4500 h.p 2πNT kg m/min All listed here 2πNT /60 watts 2πNT/4500 h.p 2πNT kg m/min ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A train weighing 196 tonnes experiences a frictional resistance of 5(11/22) per tonne. The speed of the train at the top of a down gradient 1 in 78.4 is 36 km/hour. The speed of the train after running 1 km down the slope, is 5 √3 m/sec 3 √5 m/sec 10 √5 m/sec 5 √10 m/sec 5 √3 m/sec 3 √5 m/sec 10 √5 m/sec 5 √10 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The height at which the end of a rope of length ‘l’ should be tied so that a man pulling at the other end may have the greatest tendency to overturn the pillar, is l/√2 ¾ l 2/√3 l ½ l l/√2 ¾ l 2/√3 l ½ l ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the direction of projection bisects the angle between the vertical and the inclined plane, then the range of projectile on the inclined plane is None of these Minimum Zero Maximum None of these Minimum Zero Maximum ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The maximum velocity of a body vibrating with a simple harmonic motion of amplitude 150 mm and frequency 2 vibrations/sec, is 188.5 m/sec 0.18845 m/sec 18.85 m/sec 1.885 m/sec 188.5 m/sec 0.18845 m/sec 18.85 m/sec 1.885 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² - y²) y = ω √(y - r) v = ω √(y² - r²) v = ω √(r² + y²) v = ω √(r² - y²) y = ω √(y - r) v = ω √(y² - r²) v = ω √(r² + y²) ANSWER DOWNLOAD EXAMIANS APP
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