Applied Mechanics and Graphic Statics Power developed by a torque, is 2πNT /60 watts All listed here 2πNT kg m/min 2πNT/4500 h.p 2πNT /60 watts All listed here 2πNT kg m/min 2πNT/4500 h.p ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A cable loaded with 0.5 tonne per horizontal metre span is stretched between supports in the same horizontal line 400 m apart. If central dip is 20 m, the minimum tension in the cable, will be 200 tonnes at the centre 200 tonnes at the left support 500 tonnes at the centre 200 tonnes at the right support 200 tonnes at the centre 200 tonnes at the left support 500 tonnes at the centre 200 tonnes at the right support ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A shell of mass 100 kg travelling with a velocity of 10 m/sec breaks into two equal pieces during an explosion which provides an extra kinetic energy of 20000 Joules. If the pieces continue to move in the same direction as before, then the speed of the faster one must be 30 m/sec 50 m/sec 40 m/sec 20 m/sec 30 m/sec 50 m/sec 40 m/sec 20 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rigid body suspended vertically at a point and oscillating with a small amplitude under the action of the force of gravity, is called None of these Compound pendulum Simple pendulum Second's pendulum None of these Compound pendulum Simple pendulum Second's pendulum ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If A is the amplitude of particle executing simple harmonic motion, then the total energy E of the particle is Proportional to A² Independent of A Proportional to A Proportional to 1/A² Proportional to A² Independent of A Proportional to A Proportional to 1/A² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² + y²) v = ω √(r² - y²) y = ω √(y - r) v = ω √(y² - r²) v = ω √(r² + y²) v = ω √(r² - y²) y = ω √(y - r) v = ω √(y² - r²) ANSWER DOWNLOAD EXAMIANS APP
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