Electric Circuits Phase voltages of a star connected alternator are ER = 240∠0o V, EY = 240∠-120o V and EB = 240∠ + 120o V. What is the phase sequence of the system? YBR. RYB. RBY. BYR. YBR. RYB. RBY. BYR. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A battery of E Volts is supplying a steady current to a series circuit of total resistance RΩ and inductance L Henry. A part R1 of the total resistance is suddenly short circuited. Find the expression for current flowing through the battery subsequent to the operation. i = {E / R1 - R)}(1- e - (R1 - R) t / L) i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} None of these i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} None of these i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The strength of current in 1 H inductor changes at rate of 1 A / sec. Find the voltage across it? 1 V. None of these. 0.5 V. 2 V. 1 V. None of these. 0.5 V. 2 V. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Total instantaneous power supplied by a 3 - φ AC supply to a balanced RL load is constant. pulsating with zero average. zero. pulsating with non zero average. constant. pulsating with zero average. zero. pulsating with non zero average. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits If a capacitors of capacitance 100 μF is connected across a voltage source of 10 V, then what will be the energy stored in that capacitor? 10 × 10 - 3 Joule. 5 × 10 - 2 Joule. 5 × 10 - 3 Joule. 10 × 10 6 Joule. 10 × 10 - 3 Joule. 5 × 10 - 2 Joule. 5 × 10 - 3 Joule. 10 × 10 6 Joule. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits What is the relation between time period T and frequency? T = frequency. T = 0.5 / frequency. T = 0.85 / frequency. T = 1 / frequency. T = frequency. T = 0.5 / frequency. T = 0.85 / frequency. T = 1 / frequency. ANSWER DOWNLOAD EXAMIANS APP
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