Applied Mechanics and Graphic Statics Periodic time of body moving with simple harmonic motion, is Directly proportional to its angular velocity Inversely proportional to its angular velocity Directly proportional to the square of its angular velocity Inversely proportional to the square of its angular velocity Directly proportional to its angular velocity Inversely proportional to its angular velocity Directly proportional to the square of its angular velocity Inversely proportional to the square of its angular velocity ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rope is wrapped twice around a rough pole with a coefficient of friction ‘A . It is subjected to a force Fj at one end and a gradually increasing force F2 is applied at the other end till the rope just starts slip-ping. At this instant the ratio of F2 to Fi is e*72 1 e4* e2* e*72 1 e4* e2* ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the kinetic energy and potential energy of a simple harmonic oscillator of amplitude A are both equal to half the total energy, then the displacement is equal to A/√2 A A/2 A√2 A/√2 A A/2 A√2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A shell of mass 100 kg travelling with a velocity of 10 m/sec breaks into two equal pieces during an explosion which provides an extra kinetic energy of 20000 Joules. If the pieces continue to move in the same direction as before, then the speed of the faster one must be 30 m/sec 40 m/sec 20 m/sec 50 m/sec 30 m/sec 40 m/sec 20 m/sec 50 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A uniform rod 9 m long weighing 40 kg is pivoted at a point 2 m from one end where a weight of 120 kg is suspended. The required force acting at the end in a direction perpendicular to rod to keep it equilibrium, at an inclination 60° with horizontal, is 60 kg 10 kg 100 kg 40 kg 60 kg 10 kg 100 kg 40 kg ANSWER DOWNLOAD EXAMIANS APP