Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 3h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 2h/l² × (1 – x) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be 3/2 8/5 2/3 5/8 3/2 8/5 2/3 5/8 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Parabolic formula Rankine Perry Straight line formula Parabolic formula Rankine Perry Straight line formula ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A shaft is subjected to bending moment M and a torque T simultaneously. The ratio of the maximum bending stress to maximum shear stress developed in the shaft, is M/T 2M/ T T/M 2T/M M/T 2M/ T T/M 2T/M ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum deflection due to a load W at the free end of a cantilever of length L and having flexural rigidity EI, is WL3/3EI WL3/2EI WL²/3EI WL²/2EI WL3/3EI WL3/2EI WL²/3EI WL²/2EI ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures There are two hinged semicircular arches A, B and C of radii 5 m, 7.5 m and 10 m respectively and each carries a concentrated load W at their crowns. The horizontal thrust at their supports will be in the ratio of None of these 2 : 1½ : 1 1 : 1 : 2 1 : 1½ : 2 None of these 2 : 1½ : 1 1 : 1 : 2 1 : 1½ : 2 ANSWER DOWNLOAD EXAMIANS APP
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