Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 2h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 3h/l² × (1 – x) y = 2h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 3h/l² × (1 – x) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures section modulus of a square section of side B and that of a circular section of the ratio of the diameter D, is /16 2 /15 3 /8 3 /16 /16 2 /15 3 /8 3 /16 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For the close coil helical spring of the maximum deflection is 8WD3n/d4N WD3n/d4N 2WD3n/d4N 4W²D3n/d4N 8WD3n/d4N WD3n/d4N 2WD3n/d4N 4W²D3n/d4N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum deflection of a simply supported beam of span L, carrying an isolated load at the centre of the span; flexural rigidity being EI, is WL3/48EL WL3/3EL WL3/8EL WL3/24EL WL3/48EL WL3/3EL WL3/8EL WL3/24EL ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Straight line formula Rankine Parabolic formula Perry Straight line formula Rankine Parabolic formula Perry ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A load of 1960 N is raised at the end of a steel wire. The minimum diameter of the wire so that stress in the wire does not exceed 100 N/mm² is: 4.0 mm 5.5 mm 5.0 mm 4.5 mm 4.0 mm 5.5 mm 5.0 mm 4.5 mm ANSWER DOWNLOAD EXAMIANS APP
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