Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 3h/l² × (1 – x) y = 2h/l² × (1 – x) y = 4h/l² × (1 – x) y = h/l² × (1 – x ) y = 3h/l² × (1 – x) y = 2h/l² × (1 – x) y = 4h/l² × (1 – x) y = h/l² × (1 – x ) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Beams composed of more than one material, rigidly connected together so as to behave as one piece, are known as Composite beams Compound beams Determinate beams Indeterminate beams Composite beams Compound beams Determinate beams Indeterminate beams ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel plate d × b is sandwiched rigidly between two timber joists each D × B/2 in section. The steel will be (where Young’s modulus of steel is m times that of the timber). BD² + mbd²)/4D] BD³ + mbd³)/6D] BD² + mbd²)/6D] BD² + mbd³)/4D] BD² + mbd²)/4D] BD³ + mbd³)/6D] BD² + mbd²)/6D] BD² + mbd³)/4D] ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Inertia of a rectangular section of width and depth about an axis passing the moment of through C.G. and parallel to its width is BD³/6 BD²/6 BD³/12 B²D/6 BD³/6 BD²/6 BD³/12 B²D/6 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 105 N/mm²) when subjected to a twisting moment, produces maximum shear stress of 50 N/mm 2, the angle of twist in radians, is 0.0025 0.001 0.003 0.002 0.0025 0.001 0.003 0.002 ANSWER DOWNLOAD EXAMIANS APP
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