Theory of Structures At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by Maximum compressive stress at the section Maximum tensile stress at the section Depth of the section Depth of the neutral axis Maximum compressive stress at the section Maximum tensile stress at the section Depth of the section Depth of the neutral axis ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Flat spiral springs All of these Consist of uniform thin strips Are wound by applying a torque Consist of uniform thin strips All of these Consist of uniform thin strips Are wound by applying a torque Consist of uniform thin strips ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good E = 3K (1 – 2/m) (3/2)K (1 – 2/m) = N (1 + 1/m) All of these E = 2N (1 + 1/m) E = 3K (1 – 2/m) (3/2)K (1 – 2/m) = N (1 + 1/m) All of these E = 2N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The greatest load which a spring can carry without getting permanently distorted, is called Proof resilience Proof load Stiffness Proof stress Proof resilience Proof load Stiffness Proof stress ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Shear strain energy theory for the failure of a material at elastic limit, is due to Guest or Trecas Rankine St. Venant Von Mises Guest or Trecas Rankine St. Venant Von Mises ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam which carries a uniformly distributed load has two equal overhangs. To have maximum B.M. produced in the beam least possible, the ratio of the length of the overhang to the total length of the beam, is 0.407 0.207 0.508 0.307 0.407 0.207 0.508 0.307 ANSWER DOWNLOAD EXAMIANS APP
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