Theory of Structures At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by Maximum tensile stress at the section Depth of the neutral axis Maximum compressive stress at the section Depth of the section Maximum tensile stress at the section Depth of the neutral axis Maximum compressive stress at the section Depth of the section ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel plate d × b is sandwiched rigidly between two timber joists each D × B/2 in section. The steel will be (where Young’s modulus of steel is m times that of the timber). BD³ + mbd³)/6D] BD² + mbd²)/4D] BD² + mbd³)/4D] BD² + mbd²)/6D] BD³ + mbd³)/6D] BD² + mbd²)/4D] BD² + mbd³)/4D] BD² + mbd²)/6D] ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures constant, depth of a cantilever of length of uniform strength loaded with Keeping breadth uniformly distributed load varies from zero at the free end and w l) at the fixed end l) at the fixed end 2w w l at the fixed end 3w l at the fixed end w l) at the fixed end l) at the fixed end 2w w l at the fixed end 3w l at the fixed end ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The horizontal deflection of a parabolic curved beam of span 10 m and rise 3 m when loaded with a uniformly distributed load l t per horizontal length is (where Ic is the M.I. at the crown, which varies as the slope of the arch). 50/EIc 200/EIc 100/EIc 150/EIc 50/EIc 200/EIc 100/EIc 150/EIc ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In case of a simply supported I-section beam of span L and loaded with a central load W, the length of elasto-plastic zone of the plastic hinge, is L/3 L/5 L/2 L/4 L/3 L/5 L/2 L/4 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum bending moment for a simply supported beam with a uniformly distributed load w/unit length, is WI²/8 WI²/12 WI/2 WI²/4 WI²/8 WI²/12 WI/2 WI²/4 ANSWER DOWNLOAD EXAMIANS APP
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