Engineering Mechanics One joule means that Work is done by a force of 1 dyne when it displaces a body through 1 cm Work is done by a force of 1 N when it displaces a body through 1 m Work is done by a force of 1 g when it displaces a body through 1 cm Work is done by a force of 1 kg when it displaces a body through 1 m Work is done by a force of 1 dyne when it displaces a body through 1 cm Work is done by a force of 1 N when it displaces a body through 1 m Work is done by a force of 1 g when it displaces a body through 1 cm Work is done by a force of 1 kg when it displaces a body through 1 m ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction in which the force acts. This statement is known as None of these Newton's second law of motion Newton's first law of motion Newton's third law of motion None of these Newton's second law of motion Newton's first law of motion Newton's third law of motion ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resultant of two equal forces ‘P’ making an angle ‘θ’, is given by 2P cosθ/2 2P cotθ/2 2P tanθ/2 2P sinθ/2 2P cosθ/2 2P cotθ/2 2P tanθ/2 2P sinθ/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Three forces acting on a rigid body are represented in magnitude, direction and line of action by the three sides of a triangle taken in order. The forces are equivalent to a couple whose moment is equal to Twice the area of the triangle Half the area of the triangle None of these Area of the triangle Twice the area of the triangle Half the area of the triangle None of these Area of the triangle ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If a number of forces are acting at a point, their resultant will be inclined at an angle 'θ' with the horizontal, such that tanθ = ΣV/ΣH tanθ = √(ΣV + ΣH) tanθ = ΣH/ΣV tanθ = ΣV × ΣH tanθ = ΣV/ΣH tanθ = √(ΣV + ΣH) tanθ = ΣH/ΣV tanθ = ΣV × ΣH ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The frequency of oscillation of a compound pendulum is (where kG = Radius of gyration about the centroidal axis, and h = Distance between the point of suspension and C.G. of the body.) 1/2π. √(kG² + h²/gh) 1/2π. √(gh/kG² + h²) 2π. √(kG² + h²/gh) 2π. √(gh/kG² + h²) 1/2π. √(kG² + h²/gh) 1/2π. √(gh/kG² + h²) 2π. √(kG² + h²/gh) 2π. √(gh/kG² + h²) ANSWER DOWNLOAD EXAMIANS APP
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