Electromagnetic Field Theory Ohm’s law in point from field theory can be expressed as J = E / σ. V = IR. R = ρ × ( l / A). J = σE. J = E / σ. V = IR. R = ρ × ( l / A). J = σE. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory Electric flux in coulombs emanating from any surface of a cube containing C coulombs of charge at its centre is 4πQ / 6ε. Q / 4π. Q / 6. Q / 6ε. 4πQ / 6ε. Q / 4π. Q / 6. Q / 6ε. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory Two point charges (Q and – Q) are situated at the vertex of the square. If potential at another vertex is 2 V, so potential at opposite vertex (diagonally) is Zero. 1 V. √ 2 V. 2 V. Zero. 1 V. √ 2 V. 2 V. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory According to Coulomb’s law, the force of attraction or repulsion, between to electrical charges is inversely proportional to the distance between them. directly proportional to the square of the distance between them. directly proportional to the distance between them. inversely proportional to the square of the distance between them. inversely proportional to the distance between them. directly proportional to the square of the distance between them. directly proportional to the distance between them. inversely proportional to the square of the distance between them. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory In case of surface waves the field strength at a point is directly proportional to Antenna height Wave frequency Distance of the point from the antenna Current of the antenna Antenna height Wave frequency Distance of the point from the antenna Current of the antenna ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory A conductor of length 100 cm moves at right angles to a magnetic field of flux density 1.5 Wb/m2 with a velocity of 50 m/s. The induced emf in the conductor will be 150 V. 75 V. 37.5 V. 50 V. 150 V. 75 V. 37.5 V. 50 V. ANSWER DOWNLOAD EXAMIANS APP
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