Electromagnetic Field Theory A sphere of radius with a uniform charge density ρv C/m3 shall have electric flux density at radius “r = a” equal to aρv/4 C/m2. aρv/3 C/m2. ρv/3 C/m2. aρv C/m2. aρv/4 C/m2. aρv/3 C/m2. ρv/3 C/m2. aρv C/m2. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory The force required to seperate two surfaces with a contact area measuring 5 cm by 6 cm, when flux density normal to the surface is 0.8 tesla, will be 76.4 N. 7640 N. 764 N. 76400 N. 76.4 N. 7640 N. 764 N. 76400 N. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory A metal surface with 1 meter radius and surface charge density of 20 coulombs / m2 is enclosed in a 10 m side cube. The total outward electric displacement normal to the surface of the cube is 80π coulombs. none of these. 10π coulombs. 40π coulombs. 80π coulombs. none of these. 10π coulombs. 40π coulombs. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory A wire 1 m long carries a current of 5A and is at an angle of 30o with B = 1.5 wb/m2. Magnitude of force is 3.75 N. 2 N. 5 N. 2.5 N. 3.75 N. 2 N. 5 N. 2.5 N. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory Two spheres of radius r1 and r2 are connected by a conducting wire. Each of the spheres has been given a charge Q. Now larger sphere will have greater potential. larger sphere will have smalled potential. smaller sphere will have zero potential. both of sphere will have same potential. larger sphere will have greater potential. larger sphere will have smalled potential. smaller sphere will have zero potential. both of sphere will have same potential. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory Electric field strength of charge Increase square distance. Increase distance. Decrease with distance. Decrease with square distance. Increase square distance. Increase distance. Decrease with distance. Decrease with square distance. ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS