Stoichiometry Number of gm moles of solute dissolved in one litre of a solution is called its Equivalent weight Normality Molality Molarity Equivalent weight Normality Molality Molarity ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Pick out the wrong unit conversion of calorific value. 1 BTU/lb = 2.3 kcal/kg 1 BTU/ft³ = 8.9 kcal/m³ = 0.038 MJ/m³ 1 kcal/kg = 1.8 BTU/lb = 4.186 kJ/kg 1 kcal/m³ = 0.1124 BTU/ft³ 1 BTU/lb = 2.3 kcal/kg 1 BTU/ft³ = 8.9 kcal/m³ = 0.038 MJ/m³ 1 kcal/kg = 1.8 BTU/lb = 4.186 kJ/kg 1 kcal/m³ = 0.1124 BTU/ft³ ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry The elevation in boiling point of a solution is proportional to the __________ of the solution. Molal concentration Molarity Reciprocal of the molal concentration Normality Molal concentration Molarity Reciprocal of the molal concentration Normality ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry The temperature of a gas in a closed container is 27° C. If the temperature of the gas is incresed to 300° C, then the pressure exerted is Halved Doubled Unpredictable Trebled Halved Doubled Unpredictable Trebled ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry The heats of vaporisation of CS₂, C₂H₅OH &H₂O are 26.8, 38.6 & 40.6 KJ/kg mole respectively. The order of decreasing inter-molecular forces in these liquids is H₂O > CS₂ > C₂H₅OH CS₂ > C₂H₅OH > H₂O H₂O > C₂H₅OH > CS₂ CS₂ > H₂O > C₂H₅OH H₂O > CS₂ > C₂H₅OH CS₂ > C₂H₅OH > H₂O H₂O > C₂H₅OH > CS₂ CS₂ > H₂O > C₂H₅OH ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry 80 kg of Na₂SO₄ (molecular weight = 142) is present in 330 kg of an aqueous solution. The solution is cooled such that. 80 kg of Na₂SO₄ .10H₂O crystals separate out. The weight fraction of Na₂SO₄ in the remaining solution is 0.18 1 0.24 0.18 1 0.24 ANSWER DOWNLOAD EXAMIANS APP
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