Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis through its base, is bh3/8 bh3/36 bh3/4 bh3/12 bh3/8 bh3/36 bh3/4 bh3/12 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In order to double the period of simple pendulum, the length of the string should be None of these Halved Quadrupled Doubled None of these Halved Quadrupled Doubled ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The C.G. of a solid hemisphere lies on the central radius 3r At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base 3r At distance — from the plane base At distance — from the plane base 3r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The periodic time of one oscillation for a simple pendulum is (where l = Length of the pendulum.) 2π. √(l/g) (1/2π). √(g/l) (1/2π). √(l/g) None of these 2π. √(l/g) (1/2π). √(g/l) (1/2π). √(l/g) None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics When a body of mass 'm' attains a velocity 'v' from rest in time 't', then the kinetic energy of translation is mv2 mgv2 0.5 mgv2 0.5 mv2 mv2 mgv2 0.5 mgv2 0.5 mv2 ANSWER DOWNLOAD EXAMIANS APP
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