Power Systems Mercury is choice with steam in binary vapor cycle because all of above. higher saturation temperature than other fluids. relative low vaporization pressure. higher critical temperature and pressure. all of above. higher saturation temperature than other fluids. relative low vaporization pressure. higher critical temperature and pressure. ANSWER DOWNLOAD EXAMIANS APP
Power Systems A power generating station has a maximum demand of 1000 MW. The annual load factor is 75% and plant capacity factor is 60%. Calculate the reserve capacity? 250 MW 750 MW 1250 MW 500 MW 250 MW 750 MW 1250 MW 500 MW ANSWER DOWNLOAD EXAMIANS APP
Power Systems The neutral of 10 MVA, 11 kV alternator is earthed through a resistance of 5 ohms. The fault ready is set to operate at 0.75 A. The current transformers have a ratio of 1000/5. What is the percentage of the alternator winding is protected? 88.2% 85% 15% 11.8% 88.2% 85% 15% 11.8% ANSWER DOWNLOAD EXAMIANS APP
Power Systems Graphite is use din nuclear plant as a / an electrode. fuel. coolant. moderator. electrode. fuel. coolant. moderator. ANSWER DOWNLOAD EXAMIANS APP
Power Systems Main bus bar protection scheme is /are none of these. fault bus protection. both fault bus and differential protection. differential protection. none of these. fault bus protection. both fault bus and differential protection. differential protection. ANSWER DOWNLOAD EXAMIANS APP
Power Systems A lossless power system has to serve a load of 250 MW. There are two generators(G1 and G2) in the system with cost curves C1 and C2 respectively defined as follows: C1 = PG1+0.055P²G1 C2 = 3 PG2 + 0.03 P²G2 Where PG1 and PG2 are the MW injections from generators G1 and G2 respectively. Thus, the minimum cost dispatch will be PG1 = 0 MW and PG2 = 250 MW PG1 = 150 MW and PG2 = 100 MW PG1 = 250 MW and PG2 = 0 MW PG1 = 100 MW and PG2 = 150 MW PG1 = 0 MW and PG2 = 250 MW PG1 = 150 MW and PG2 = 100 MW PG1 = 250 MW and PG2 = 0 MW PG1 = 100 MW and PG2 = 150 MW ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS