Engineering Mechanics Mass moment of inertia of a thin rod about its one end is ___________ the mass moment of inertia of the same rod about its mid-point Twice Thrice Four times Same as Twice Thrice Four times Same as ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will Remain horizontal None of these Slant down towards direction of pull Slant up towards direction of pull Remain horizontal None of these Slant down towards direction of pull Slant up towards direction of pull ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The forces which do not meet at one point and their lines of action do not lie on the same plane are known as Non-coplanar concurrent forces None of these Coplanar concurrent forces Coplanar non-concurrent forces Non-coplanar concurrent forces None of these Coplanar concurrent forces Coplanar non-concurrent forces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The unit of angular acceleration is rad/s2 N-m m/s2 m/s rad/s2 N-m m/s2 m/s ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The frequency of oscillation of a compound pendulum is (where kG = Radius of gyration about the centroidal axis, and h = Distance between the point of suspension and C.G. of the body.) 2π. √(kG² + h²/gh) 1/2π. √(kG² + h²/gh) 2π. √(gh/kG² + h²) 1/2π. √(gh/kG² + h²) 2π. √(kG² + h²/gh) 1/2π. √(kG² + h²/gh) 2π. √(gh/kG² + h²) 1/2π. √(gh/kG² + h²) ANSWER DOWNLOAD EXAMIANS APP
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