Engineering Mechanics Mass moment of inertia of a thin rod about its one end is ___________ the mass moment of inertia of the same rod about its mid-point Same as Twice Thrice Four times Same as Twice Thrice Four times ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The force required to move the body up the plane will be minimum if it makes an angle with the inclined plane __________ the angle of friction. Equal to Less than None of these Greater than Equal to Less than None of these Greater than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG + Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The coefficient of friction depends upon Shape of the surfaces Area of contact All of these Nature of surfaces Shape of the surfaces Area of contact All of these Nature of surfaces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In order to completely specify angular displacement by a vector, it must fix Magnitude of angular displacement All of these Sense of angular displacement Direction of the axis of rotation Magnitude of angular displacement All of these Sense of angular displacement Direction of the axis of rotation ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a thin rod of mass 'm' and length 'l', about an axis through its centre of gravity and perpendicular to its length is ml2/12 ml2/8 ml2/4 ml2/ 6 ml2/12 ml2/8 ml2/4 ml2/ 6 ANSWER DOWNLOAD EXAMIANS APP
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