Engineering Mechanics Mass moment of inertia of a thin rod about its one end is ___________ the mass moment of inertia of the same rod about its mid-point Thrice Twice Four times Same as Thrice Twice Four times Same as ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will Remain horizontal Slant down towards direction of pull None of these Slant up towards direction of pull Remain horizontal Slant down towards direction of pull None of these Slant up towards direction of pull ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A machine having an efficiency less than 50%, is known as Neither reversible nor non-reversible machine Non-reversible machine Reversible machine Ideal machine Neither reversible nor non-reversible machine Non-reversible machine Reversible machine Ideal machine ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Whenever a force acts on a body and the body undergoes a displacement, then Power is being transmitted Body has kinetic energy of translation None of these Work is said to be done Power is being transmitted Body has kinetic energy of translation None of these Work is said to be done ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If a number of forces are acting at a point, their resultant is given by √[(∑V)2 + (∑H)2] (∑V)2 +(∑H)2 +2(∑V)(∑H) (∑V)2 + (∑H)2 √[(∑V)2 +(∑H)2 +2(∑V)(∑H)] √[(∑V)2 + (∑H)2] (∑V)2 +(∑H)2 +2(∑V)(∑H) (∑V)2 + (∑H)2 √[(∑V)2 +(∑H)2 +2(∑V)(∑H)] ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 IP = IG / Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
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