Irrigation Engineering Lining of irrigation channels decreases the waterlogging area does not change the water logging area None of these increases the waterlogging area decreases the waterlogging area does not change the water logging area None of these increases the waterlogging area ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering Irrigation canals are generally aligned along Valley line Contour line Straight line Ridge line Valley line Contour line Straight line Ridge line ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering Regime conditions in a channel may occur if Discharge is constant All listed here Silt grade and silt charge are constant Channel flows uniformly in incoherent alluvium as that transported in suspension Discharge is constant All listed here Silt grade and silt charge are constant Channel flows uniformly in incoherent alluvium as that transported in suspension ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering Assertion A : To estimate the rainfall over a catchment, the number of raingauges required per unit area is large for hilly areas.Reason R : Rainfall gradient is steep. Select your correct answer according to the coding system given below : Both A and R are true but R is not the correct explanation of A Both A and R are true and R is the correct explanation of A A is true but R is false A is false but R is true Both A and R are true but R is not the correct explanation of A Both A and R are true and R is the correct explanation of A A is true but R is false A is false but R is true ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering The relation between probability (P) and recurrence interval (T) is given by PT = 1 PT2 = 1 P/T = 1 P/T2 = 1 PT = 1 PT2 = 1 P/T = 1 P/T2 = 1 ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering According to Kennedy, the critical velocity (V₀) in meters in a channel is the mean velocity which keeps the channel free from silting or scouring. Its value is given by (where m is critical velocity ratio and D is the depth of the channel). V₀ = 0.55 mD0.64 V₀ = 0.55 mD0.54 V₀ = 0.84 mD0.64 V₀ = 0.84 mD0.54 V₀ = 0.55 mD0.64 V₀ = 0.55 mD0.54 V₀ = 0.84 mD0.64 V₀ = 0.84 mD0.54 ANSWER DOWNLOAD EXAMIANS APP
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