Engineering Thermodynamics Kinetic energy of the molecules in terms of absolute temperature (T) is proportional to J T Vr J² J T Vr J² ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The area under the temperature-entropy curve (T – s curve) of any thermodynamic process represents Heat absorbed Heat rejected Either heat absorbed or heat rejected None of the listed here Heat absorbed Heat rejected Either heat absorbed or heat rejected None of the listed here ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics According to which law, all perfect gases change in volume by 1/273th of their original volume at 0°C for every 1°C change in temperature when pressure remains constant Gay Lussac’s law Charles' law Boyle's law Joule's law Gay Lussac’s law Charles' law Boyle's law Joule's law ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The absolute zero pressure will be When molecular momentum of the system becomes zero At sea level At the temperature of - 273 K At the center of the earth When molecular momentum of the system becomes zero At sea level At the temperature of - 273 K At the center of the earth ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Zeroth law of thermodynamics Deals with reversibility and irreversibility of process Deals with conversion of mass and energy Deals with heat engines States that if two systems are both in equilibrium with a third system, they are in thermal equilibrium with each other Deals with reversibility and irreversibility of process Deals with conversion of mass and energy Deals with heat engines States that if two systems are both in equilibrium with a third system, they are in thermal equilibrium with each other ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics To convert volumetric analysis to gravimetric analysis, the relative volume of each constituent of the flue gases is Multiplied by its density Multiplied by its molecular weight Multiplied by its specific weight Divided by its molecular weight Multiplied by its density Multiplied by its molecular weight Multiplied by its specific weight Divided by its molecular weight ANSWER DOWNLOAD EXAMIANS APP
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