DGVCL Exam Paper (11-12-2011) It is difficult interrupt a capacitive current because Current magnitude is very small It has a leading power factor Stored energy in the capacitor is very high The restriking voltage can be high Current magnitude is very small It has a leading power factor Stored energy in the capacitor is very high The restriking voltage can be high ANSWER DOWNLOAD EXAMIANS APP
DGVCL Exam Paper (11-12-2011) If the fault current is 2000 A, the relay plug setting is 50% and the CT ratio is 400/5, the plug setting multiple will be 10 50 15 25 10 50 15 25 ANSWER DOWNLOAD EXAMIANS APP
DGVCL Exam Paper (11-12-2011) Permittivity is expressed in terms of farad/sq. m. N/m Weber /m Farad/m farad/sq. m. N/m Weber /m Farad/m ANSWER DOWNLOAD EXAMIANS APP
DGVCL Exam Paper (11-12-2011) If the percentage reactance of the system upto the point of fault is 20% and the base kVA is 10,000 the short ciruit kVA is 60 MVA 20 MVA 10 MVA 50 MVA 60 MVA 20 MVA 10 MVA 50 MVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Short circuit kVA = Base kVA/%X
DGVCL Exam Paper (11-12-2011) A 3 phase, 6 pole induction motor operates on 440 V, 50 Hz, supply. If the actual speed of the motor is 960 rpm the slip will be 0.4 % 5 % 4 % 6 % 0.4 % 5 % 4 % 6 % ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ns = 120f/PSlip=(Ns-Nr)/NsNs = 1000 and Nr = 960 from equation of slip, S = (1000-960)/1000S = 0.04 or 4%
DGVCL Exam Paper (11-12-2011) The transient stability of a power system can be improved by Increasing the turbine valve opening Single pole switching of circuit breakers Phase shifting transformer Excitation control Increasing the turbine valve opening Single pole switching of circuit breakers Phase shifting transformer Excitation control ANSWER DOWNLOAD EXAMIANS APP
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