Stoichiometry Isotopes are atoms having the same Atomic mass Number of neutrons None of these Mass number Atomic mass Number of neutrons None of these Mass number ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH₄ + 2O₂ → CO₂ + 2H₂O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. Mole fraction of water vapour in the product gases is about 0.67 0.33 0.40 0.19 0.67 0.33 0.40 0.19 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry A butane isomerisation process produces 70 kmole/hr of pure isobutane. A purge stream removed continuously, contains 85% n-butane and 15% impurity (mole%). The feed stream is n-butane containing 1% impurity (mole%). The flow rate of the purge stream will be 4 kmole/hr 5 kmole/hr 3 kmole/hr 6 kmole/hr 4 kmole/hr 5 kmole/hr 3 kmole/hr 6 kmole/hr ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Equal masses of CH₄ and H₂ are mixed in an empty container. The partial pressure of hydrogen in this container expressed as the fraction of total pressure is 8/9 5/9 1/2 1/9 8/9 5/9 1/2 1/9 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry If 1 Nm³ of O₂ contains 'N' number of molecules, then number of molecules in 2Nm³ of SO₂ will be 2N 4N N/2 N 2N 4N N/2 N ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Saturated solution of benzene in water is in equilibrium with a mixture of air and vapours of benzene and water at room temperature and pressure. Mole fraction of benzene in liquid is xB and the vapour pressures of benzene and water at these conditions are PvB and Pvw respectively. The partial pressure of benzene in air-vapour mixture is XB.Patm PvB (Patm - Pvw)xB XB.PvB XB.Patm PvB (Patm - Pvw)xB XB.PvB ANSWER DOWNLOAD EXAMIANS APP