Analog Electronics In the constant-current region, how will the IDS change in an n-channel JFET? As VGS increases ID remains constant. As VGS increases ID increases. As VGS decreases ID remains constant. As VGS decreases ID decreases. As VGS increases ID remains constant. As VGS increases ID increases. As VGS decreases ID remains constant. As VGS decreases ID decreases. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics In deriving ac equivalent circuit for an amplifier circuit we short circuit All transistors All resistors All capacitors All inductors All transistors All resistors All capacitors All inductors ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics When testing an npn transistor using an ohmmeter, the collector-emitter resistance will be low when the transistor is defective. the transistor is normal. the emitter is positive in respect to the collector. the collector is positive in respect to the emitter. the transistor is defective. the transistor is normal. the emitter is positive in respect to the collector. the collector is positive in respect to the emitter. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics What is the majority carriers of P type material ? None of these Holes Protons Electrons None of these Holes Protons Electrons ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics The input impedance of the base of an emitter follower is usually low. high. shorted to ground. open. low. high. shorted to ground. open. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics An npn BJT has gm=38mA/v, cµ =10¯14 F, cπ =10¯13F and DC current gain β0=90.For this transistor fT & fβ are fT =1.33 x 1012 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.64 x 108 Hz fT =1.64 x 108 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.33 x 1012 Hz fT =1.33 x 1012 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.64 x 108 Hz fT =1.64 x 108 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.33 x 1012 Hz ANSWER DOWNLOAD EXAMIANS APP
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