Theory of Structures In plastic analysis, the shape factor for a circular section, is 1.5 1.3 1.7 1.2 1.5 1.3 1.7 1.2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A close coil helical spring of mean diameter D consists of n coils of diameter d. If it carries an axial load W, the energy stored in the spring, is 4W²Dn/d4N 4W²D3n/d4N 4WD²n/d4N 4W²D3n²/d4N 4W²Dn/d4N 4W²D3n/d4N 4WD²n/d4N 4W²D3n²/d4N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In case of a simply supported rectangular beam of span L and loaded with a central load W, the length of elasto-plastic zone of the plastic hinge, is L/5 L/2 L/4 L/3 L/5 L/2 L/4 L/3 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum magnitude of shear stress due to shear force F on a rectangular section of area A at the neutral axis, is F/A 3F/2A F/2A 2F/3A F/A 3F/2A F/2A 2F/3A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is [W (2 + f/G)]/A (1 – g/f)/A [W (1 + f/ G)]/ A [W (2 + g/f)]/A [W (2 + f/G)]/A (1 – g/f)/A [W (1 + f/ G)]/ A [W (2 + g/f)]/A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 4h/l² × (1 – x) y = h/l² × (1 – x ) y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) y = 4h/l² × (1 – x) y = h/l² × (1 – x ) y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) ANSWER DOWNLOAD EXAMIANS APP
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