Digital Electronics In K-map simplification, a group of four adjacent 1s leads to a term with three literals less than the total number of variables one literal less than the total number of variables two literals less than the total number of variables four literals less than the total number of variables three literals less than the total number of variables one literal less than the total number of variables two literals less than the total number of variables four literals less than the total number of variables ANSWER DOWNLOAD EXAMIANS APP
Digital Electronics A computer has a word length of 8 bits (including sign). It is required to determine the range of integers that can be stored in the computer. If 1’s complement is used to represent the numbers, then the range will be -128 to 127 -256 to 255 -127 to 127 -256 to 256 -128 to 127 -256 to 255 -127 to 127 -256 to 256 ANSWER DOWNLOAD EXAMIANS APP
Digital Electronics The binary equivalent of hexadecimal number 4F2D is 0100 1111 0010 1100 0100 1111 0010 1101 0101 1111 0010 1100 0100 1110 0010 1101 0100 1111 0010 1100 0100 1111 0010 1101 0101 1111 0010 1100 0100 1110 0010 1101 ANSWER DOWNLOAD EXAMIANS APP
Digital Electronics Assuming 8 bits for data, 1 bit for parity, I start bit and 2 stop bits, the number of characters that 1200 BPS communication line can transmit is. 10 CPS None of these 120 CPS 12 CPS 10 CPS None of these 120 CPS 12 CPS ANSWER DOWNLOAD EXAMIANS APP
Digital Electronics X = 01110 and Y = 11001 are two 5-bit binary numbers represented in 2’s complement format. The sum of X and Y in 2’s complement format using 6 bits is 001000 100111 0001111 101001 001000 100111 0001111 101001 ANSWER DOWNLOAD EXAMIANS APP
Digital Electronics The inputs of a NAND gate are connected together. The resulting circuit is ___________. OR gate None of these NOT gate AND gate OR gate None of these NOT gate AND gate ANSWER DOWNLOAD EXAMIANS APP
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