Chemical Engineering Thermodynamics In case of steady flow compression polytropic process (PVn = constant), the work done on air is the lowest, when N = 0 N = 1 N = 1.66 N = y = 1.4 N = 0 N = 1 N = 1.66 N = y = 1.4 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Lowering of condenser temperature (keeping the evaporator temperature constant) in case of vapour compression refrigeration system results in Decreased COP Increased or decreased COP ; depending upon the type of refrigerant Same COP Increased COP Decreased COP Increased or decreased COP ; depending upon the type of refrigerant Same COP Increased COP ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The Maxwell relation derived from the differential expression for the Helmholtz free energy (dA) is (∂S/∂V)T = (∂P/∂T)V (∂S/∂P)T = -(∂V/∂T)P (∂T/∂V)S = -(∂P/∂S)V (∂V/∂S)P = (∂T/∂P)S (∂S/∂V)T = (∂P/∂T)V (∂S/∂P)T = -(∂V/∂T)P (∂T/∂V)S = -(∂P/∂S)V (∂V/∂S)P = (∂T/∂P)S ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics When liquid and vapour phases of one component system are in equilibrium (at a given temperature and pressure), the molar free energy is Same in both the phases More in vapour phase More in liquid phase Replaced by chemical potential which is more in vapour phase Same in both the phases More in vapour phase More in liquid phase Replaced by chemical potential which is more in vapour phase ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Compressibility factor (i.e., the ratio of actual volume of gas to the volume predicted by ideal gas law) for all gases are Same at the same reduced temperature Always greater than one Same at the same reduced pressure Both B & C Same at the same reduced temperature Always greater than one Same at the same reduced pressure Both B & C ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics At normal boiling point, molar entropy of vaporisation is __________ Joule/K°.mole. 92 192 142 72 92 192 142 72 ANSWER DOWNLOAD EXAMIANS APP
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