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Engineering Thermodynamics

Engineering Thermodynamics
In an irreversible process, there is a

Gain of heat
No gain of heat
Loss of heat
No loss of heat

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Engineering Thermodynamics
One reversible heat engine operates between 1600 K and T2 K and another reversible heat engine operates between T2 K and 400 K. If both the engines have the same heat input and output, then temperature T2 is equal to

800 K
1000 K
1400 K
1200 K

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Engineering Thermodynamics
For a perfect gas, according to Boyle’s law (where P = Absolute pressure, V = Volume and T = Absolute temperature)

T/P = constant, if v is kept constant
P v = constant, if T is kept constant
P/T = constant, if v is kept constant
V/T = constant, if p is kept constant

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Engineering Thermodynamics
The specific heat of water is

1.817
None of these
4.187
2.512

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Engineering Thermodynamics
Otto cycle efficiency is higher than Diesel cycle efficiency for the same compression ratio and heat input because in Otto cycle

Expansion and compression are isentropic
Combustion is at constant volume
Maximum temperature is higher
Heat rejection is lower

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Engineering Thermodynamics
The variables which control the physical properties of a perfect gas are

Temperature of the gas
Volume occupied by the gas
All of these
Pressure exerted by the gas

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MORE MCQ ON Engineering Thermodynamics

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