MGVCL Exam Paper (30-07-2021 Shift 2) In a typical DC micro grid, hybrid storage system is a combination of Lead acid battery and ultra capacitor / super capacitor Lead acid battery and Capacitor None of these Lead acid battery and Lithium ion battery Lead acid battery and ultra capacitor / super capacitor Lead acid battery and Capacitor None of these Lead acid battery and Lithium ion battery ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Hybrid storage system is a combination of microturbines, fuel cells, photovoltaics (PV), Lead acid battery and ultra or super capacitors etc.
MGVCL Exam Paper (30-07-2021 Shift 2) A wire pilot is generally economical for distances up to 75 km to 100 km 20 to 25 km 30 km to 60 km 10 km to 15 km 75 km to 100 km 20 to 25 km 30 km to 60 km 10 km to 15 km ANSWER EXPLANATION DOWNLOAD EXAMIANS APP A wire pilot is generally economical for distances up to 5 or 10 miles, beyond which a carrier-current pilot usually becomes more economical.
MGVCL Exam Paper (30-07-2021 Shift 2) Vikram Seth is associated with which of the following fields? Sports Literature Politician Music Sports Literature Politician Music ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Transistors were used in ____ of Computers. Fourth Generation Third Generation First Generation Second Generation Fourth Generation Third Generation First Generation Second Generation ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) સોહેલ ખાન : મલાયકા અરોર :: સૈફ અલી ખાન : ?? કિરણ ખેર પરવીન બાબી માધુરી દિક્ષિત અમૃતા સિંહ કિરણ ખેર પરવીન બાબી માધુરી દિક્ષિત અમૃતા સિંહ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 1000 kVA ONAN cooled transformer has a load of 500 kVA throughout the day except for a period of 4 hours. What is the permissible overload for a duration of four hours. Assume the permissible load kVA as a fraction of rated kVA is 1.24. 2480 kVA 620 kVA 930 kVA 1240 kVA 2480 kVA 620 kVA 930 kVA 1240 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Permissible overload = Full load kVA*factor for permissible load= 1000*1.24= 1240 kVA