MGVCL Exam Paper (30-07-2021 Shift 2) In a synchronous motor with field under excited, the power factor will be lagging unity leading zero lagging unity leading zero ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For synchronous motor,Under excitation - Lagging power factorOver excitation - Leading power factorFor synchronous generatorUnder excitation - Leading power factorOver excitation - lagging power factor
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is not a Font style in Microsoft Word? Regular Italic Bold Superscript Regular Italic Bold Superscript ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) What is the full form of the acronym 'AIDS' in diseases? Acquire in Deficiency Syndrome Assert in Dander Syndrome Acquired Immune Deficiency Syndrome Amino Intersect Deficiency Syndrome Acquire in Deficiency Syndrome Assert in Dander Syndrome Acquired Immune Deficiency Syndrome Amino Intersect Deficiency Syndrome ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) In the context of smart meters, the term 'SMETS' stand for Smart Metering Equipment Technical Specifications Smart Monitoring Equipment Technical Specifications Standard Metering Equipment Technical Specifications Standard Monitoring Equipment Technical Specifications Smart Metering Equipment Technical Specifications Smart Monitoring Equipment Technical Specifications Standard Metering Equipment Technical Specifications Standard Monitoring Equipment Technical Specifications ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 50 Hz synchronous generator is connected to an infinite bus through a line. The p.u. reactances of generator and the line are j0.3 p.u. and j0.2 p.u. respectively. The generator no load voltage is 1.1 p.u. and that of infinite bus is 1.0 p.u. The inertia constant of the generator is 4 MW-sec/MVA. Determine the frequency of natural oscillations if the generator is loaded to 60% of its maximum power transfer capacity and small perturbation in power is given. 1.62 Hz 1.32 Hz 1.52 Hz 1.42 Hz 1.62 Hz 1.32 Hz 1.52 Hz 1.42 Hz ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Frequency of natural oscillation is given by,fn = {((dPe/dδ)at(δo))/M)}dPe/dδ = ((V1*V2)/X*(cosδ))= (11/05)*cosδ= (11/0.5)*0.5M = (H*s)/(πf)= 4/(50π)fn = (1.76*(3/50π))= 9.4 rad/sec = 1.32 Hz
MGVCL Exam Paper (30-07-2021 Shift 2) Recently, India and Benin signed MoUs on education, health and ____ Trading Defence Against Corruption e-visa facilities Trading Defence Against Corruption e-visa facilities ANSWER DOWNLOAD EXAMIANS APP
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