Surveying In a spherical triangle ABC, right angled at C, sin b equals cot A tan a tan a cot A cos a sin A sin a cos A cot A tan a tan a cot A cos a sin A sin a cos A ANSWER DOWNLOAD EXAMIANS APP
Surveying The angle between the observer's meridian and declination circle of a heavenly body, is known as Declination Hour angle Azimuth Right ascension Declination Hour angle Azimuth Right ascension ANSWER DOWNLOAD EXAMIANS APP
Surveying The correction applied to the measured base of length ‘L’ is Tension = (P - Ps)L/AE Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports All of these Sag = L³w²/24P² where w is the weight of tape/m Tension = (P - Ps)L/AE Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports All of these Sag = L³w²/24P² where w is the weight of tape/m ANSWER DOWNLOAD EXAMIANS APP
Surveying The latitude of a place was obtained by subtracting the zenith distance of a star from its declination, the observed star was between Zenith and pole Horizon and equator Pole and horizon Equator and zenith Zenith and pole Horizon and equator Pole and horizon Equator and zenith ANSWER DOWNLOAD EXAMIANS APP
Surveying If the equatorial distance between two meridians is 100 km, their distance at 60° latitude will be 600 km 500 km 1000 km 800 km 600 km 500 km 1000 km 800 km ANSWER DOWNLOAD EXAMIANS APP
Surveying If E is the spherical excess and R the radius of the earth, the surface area of the triangle, is πR²E/180° πR²E/270° πR²E/360° πR²E/90° πR²E/180° πR²E/270° πR²E/360° πR²E/90° ANSWER DOWNLOAD EXAMIANS APP
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