Engineering Thermodynamics In a reversible adiabatic process, the ratio of T1/T2 is equal to (p2/p1)γ - 1/ γ (p1/p2)γ - 1/ γ (v1/v2)γ - 1/ γ (v2/v1)γ - 1/ γ (p2/p1)γ - 1/ γ (p1/p2)γ - 1/ γ (v1/v2)γ - 1/ γ (v2/v1)γ - 1/ γ ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of gas constant (R) in S. I. units is 0.287 J/kgK 28.7 J/kgK 287 J/kgK 2.87 J/kgK 0.287 J/kgK 28.7 J/kgK 287 J/kgK 2.87 J/kgK ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The total energy of a molecule is shared equally by the various degrees of freedom possessed by it. This law is known as Law of degradation of energy Law of conservation of energy None of the listed here Law of equipartition of energy Law of degradation of energy Law of conservation of energy None of the listed here Law of equipartition of energy ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The gas constant (R) is equal to the Difference of two specific heats Sum of two specific heats Ratio of two specific heats Product of two specific heats Difference of two specific heats Sum of two specific heats Ratio of two specific heats Product of two specific heats ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics No liquid can exist as liquid at Centre of earth 273°K Vacuum Zero pressure Centre of earth 273°K Vacuum Zero pressure ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of 1 mm of Hg is equal to 1.333 N/m2 133.3 N/m2 13.33 N/m2 1333 N/m2 1.333 N/m2 133.3 N/m2 13.33 N/m2 1333 N/m2 ANSWER DOWNLOAD EXAMIANS APP
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