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Alligation or Mixture problems

Alligation or Mixture problems
In a colored picture of blue and yellow color, blue and yellow color is used in the ratio of 4:3 respectively. If in upper half, blue : yellow is 2:3, then in the lower half blue : yellow is

9 : 26
1 : 1
26 : 9
2 : 1

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Alligation or Mixture problems
A man buys milk at Rs. 5 a litre and mixes it with water. By selling the mixture at Rs. 4 a litre he gains 121/2 % on his outlay. How much water did each litre of the mixture contain?

32 litre 13
32 litre 45
None of these
13 litre 45

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Alligation or Mixture problems
A jar full of whisky contains 40 % of alcohol. A part of this whisky is replaced by another containing 19 % alcohol and now the percentage of alcohol was found to be 26. The quantity of whisky replaced is ?

1 3
2 5
2 3
3 5

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Alligation or Mixture problems
In what ratio must a mixture of 20% milk strength be mixed with that of 60% milk strength so as to get a new mixture of 25% milk strength?

7 : 1
5 : 2
4 : 1
9 : 2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Ratio of milk and water = 2 : 1Quantity of milk = 60 X 2/3 = 40 litreQuantity of water = 20 litreTo make ratio, 1: 2, we have to double the water that of milkSo, water should be 80 litre.That means 80 ? 20 = 60 litre water to be added.

Alligation or Mixture problems
In what ratio of water be mixed with milk to gain 16 2/ 3 % on selling the mixture at cost price?

1 : 6
4 : 3
6 : 1
2 : 3

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let C.P. of 1 liter milk be Re. 1, Gain = 16 2/3 % = 50/3 %and S.P. of 1 liter mixture = Re. 1 then C.P. of 1 liter mixture = (1 x (100 x 3) / 350) = Re. (6 / 7) By the rule of alligation,Hence, required ratio = (1/ 7) : (6 / 7) = 1 : 6

Alligation or Mixture problems
One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.

26 %
29 %
27 %
21 %

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135  X = 27 So, required percentage of benzene = 27 %

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