Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to: 55/601 120/11 11/120 601/55 55/601 120/11 11/120 601/55 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 23/37 11/13 31/45 17/29 23/37 11/13 31/45 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ? 16 4 15 10 16 4 15 10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: 408 508 308 208 408 508 308 208 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = (11 x 7700/275) = 308.
Problems on H.C.F and L.C.M The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 128 127 126 125 128 127 126 125 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5)= H.C.F. of 1651 and 2032 = 127.
Problems on H.C.F and L.C.M The largest four-digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case,is : 9834 8739 9831 9893 9834 8739 9831 9893 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS