Area Problems If the sides of a squares is increased by 25%, then the area of the squares will be increased by 56.25% 53.75% 50% 125% 56.25% 53.75% 50% 125% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required increment = 2a + [a2 / 100] %= 2 x 25 + [(252)/100)] %= 50 + (625/100)% = 56.25%
Area Problems If the radius of a circle is increased by 6%, find the percentage increase in its area. 15% 17% 8.39% 12.36% 15% 17% 8.39% 12.36% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, a = 6 According to the formula,Percentage increase in area= 2a + [a2/100]%= 2 x 6 + [36/100]%= (12 + 0.36)%= 12.36%
Area Problems A triangle with three equal sides has its area equal to 3?3 sq cm . Find its perimeter . 7?3 cm 2?3 cm 6?3 cm 5?3 cm 7?3 cm 2?3 cm 6?3 cm 5?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,?3a2/4 = 3?3 [ side = a, and area = ?3a2/4] ? a2/4 = 3 ? a2 = 3 x 4 ? a = 2?3? Required perimeter = 3a =3 x 2?3 = 6?3 cm
Area Problems The area of a rectangle, 144 m long is the same as that of a square having a side 84 m long. The width of the rectangle is? 14 m 7 m 49 m Cannot be determined 14 m 7 m 49 m Cannot be determined ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the square = (84 + 84) m2Area of the rectangle = (144 x width) m2From question both area would be same,? Width = (84 x 84) / 144 m = 49 m
Area Problems A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is rs.258 rs.358 rs.158 rs.58 rs.258 rs.358 rs.158 rs.58 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x (75/100) = Rs. 258
Area Problems If the diagonal of a square is double, how does the area of the square change? Becomes two fold Becomes four fold None of these Becomes three fold Becomes two fold Becomes four fold None of these Becomes three fold ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas = area of original square / area of new square = [ d2 / 2 ] / [ (2d)2 / 2 ] = 1/4? New area becomes 4 fold.
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