Area Problems If the sides of a squares is increased by 25%, then the area of the squares will be increased by 50% 56.25% 125% 53.75% 50% 56.25% 125% 53.75% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required increment = 2a + [a2 / 100] %= 2 x 25 + [(252)/100)] %= 50 + (625/100)% = 56.25%
Area Problems A rectangular carpet has an area of 120 sq. m and a perimeter of 46 m . The length of its diagonal is? 20 m 17 m 16 m 15 m 20 m 17 m 16 m 15 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length = a metres and breadth = b metres Then, 2(a+b)= 46 ? (a+b) =23 and ab =120 ? Diagonal = ?a2 + b2?(23)2-2 x 120?289 = 17 m
Area Problems The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre. Rs.18500 Rs.17500 Rs.16500 Rs.15500 Rs.18500 Rs.17500 Rs.16500 Rs.15500 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 5.5 × 3.75 sq. metre. Cost for 1 sq. metre. = Rs. 800 Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500
Area Problems The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is 1078 154 49 378 1078 154 49 378 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The diameter is equal to the shortest side of the rectangle. So radius= 14/2 = 7cm. Therefore, area of circle = (r)2 = (22/7) x 49 = 154 cm2
Area Problems A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor. 166 146 136 176 166 146 136 176 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of the room = 544 x 374 sq.cm size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm area of 1 tile = 34x34 sq cm no. of tiles required = (544 x 374) / (34 x 34) = 176
Area Problems The diameter of a circle is 105 cm less than the circumference. What is the diameter of the circle? 44 cm 48 cm 49 cm 46 cm 44 cm 48 cm 49 cm 46 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? ?d-d = 105 cm ? (? -1 ) d = 105 cm? [(22/7)-1] x d = 105 cm? d = (7/15) x 105 cm = 49 cm
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