Area Problems If the sides of a rectangle are increased by 10% find the percentage increased in its diagonals. 18% 20% 15% 10% 18% 20% 15% 10% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the formula,? Percentage increase in sides = 10%? Percentage increase diagonals = 10%
Area Problems The ratio between the lenght and the breadth of a rectangle is 2 : 1. If breadth is 5 cm less than the length, what will be the parimeter of the rectangle? 25 cm 35 cm 30 cm 40 cm 25 cm 35 cm 30 cm 40 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length = 2x and breadth = xAccording to the question, 2x - x = 5 ? x = 5? Required perimeter = 2(2x + x) = 6x= 30 cm
Area Problems The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is? none of these 280 m 260 m 360 m none of these 280 m 260 m 360 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m
Area Problems An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is: 2.02% 4% 2% 4.04% 2.02% 4% 2% 4.04% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 100 cm is read as 102 cm. ∴ A1 = (100 x 100) cm2 and A2 (102 x 102) cm2. (A2 - A1) = [(102)2 - (100)2] = (102 + 100) x (102 - 100) = 404 cm2. ∴ Percentage error = ❨ 404 x 100 ❩% = 4.04%
Area Problems The area of a circle of radius 5 is numerically what percent its circumference? 450% 250% 150% 350% 450% 250% 150% 350% ANSWER DOWNLOAD EXAMIANS APP
Area Problems The Number of rounds that a wheel of diameter 7/11 m will make in going 4 km, is? 2000 1700 1500 1000 2000 1700 1500 1000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Number of round = total distance / circumference of wheel.= (4 x 1000) / ?d= (4 x 1000) / ( 22/7 x 7/11) = 2000
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