Area Problems If the sides of a rectangle are increased by 10% find the percentage increased in its diagonals. 18% 10% 20% 15% 18% 10% 20% 15% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the formula,? Percentage increase in sides = 10%? Percentage increase diagonals = 10%
Area Problems The radius of the wheel of a vehicle is 70 cm. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle is? 36.25 km/hr. 32.72 km/hr. 31.68 km/hr. 29.46 km/hr. 36.25 km/hr. 32.72 km/hr. 31.68 km/hr. 29.46 km/hr. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference = 2?r = 2 x (22 / 7) x 70 cm = 440 cm Distance travelled in 10 revolutions = 440 x 10 cm = 4400 cm = 44 m? Speed = distance / time= 44 / 5 m/sec= (44 / 5) x (18 / 5) km/hr = 31.68 km/hr
Area Problems The perimeter of two square is 12 cm and 24 cm. The area of the bigger square is how many times that of the smaller? 4 times 3 times 2 times 5 times 4 times 3 times 2 times 5 times ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of area of 2 squares = (ratio of perimeter of 2 squares)2= (24/12)2= 4
Area Problems The radius of a circular field is 25 m. Find the area of the field. 125 ? sq m 625 ? sq m 135 ? sq m 25 ? sq m 125 ? sq m 625 ? sq m 135 ? sq m 25 ? sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = ?r2 = ? x 25 x 25 = 625? sq m.
Area Problems One side of a parallelogram is 8.06 cm and its perpendicular distance from opposite side is 2.08 cm. What is the approximate area of the parallelogram? 14.56 cm2 12.56 cm2 16.76 cm2 22.56 cm2 14.56 cm2 12.56 cm2 16.76 cm2 22.56 cm2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of parallelogram = Base x Height = 8.06 x 2.08 = 16.76 cm2
Area Problems The ratio of length and breadth of a rectangle is 5 : 3 .If length is 8 m more than breadth, find the area of the rectangle. 250 sq m 240 sq m 300 sq m 185 sq m 250 sq m 240 sq m 300 sq m 185 sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length of rectangle = 5kand breadth of rectangle = 3kAccording to the quecation,5k - 3k = 8 ? 2k =8? k = 4? Lenght = 5k = 5 x 4 = 20 mBreadth = 3k = 3 x 4 = 12 m? Required area = Lenght x Breadth = 20 x 12 = 240 sq m
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