Area Problems If the length of diagonal AC of a square ABCD is 5.2 cm then area of the square ABCD is? 15.12 sq.cm 12.62 sq.cm 13.52 sq.cm 10 sq.cm 15.12 sq.cm 12.62 sq.cm 13.52 sq.cm 10 sq.cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 1/2 x (Diagonal)2= (1/2) x 5.2 x 5.2 cm2= 13.52 cm2
Area Problems A circular piece of thin wire is converted into a rhombus of side 11 cm. Find the diameter of the circular piece? 14 cm 3.5 cm 28 cm 7 cm 14 cm 3.5 cm 28 cm 7 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circular piece is 4 x 11 = 44 cm long, Then Circumference of circle is given by, 44 = pi x D, where D is the diameter D = 44 / pi Take pi = 22 / 7, then D = 44 / (22/7) = (44 x 7) / 22 D = 14 cm.
Area Problems The area of an equilateral triangle whose side is 8 cms is? 64 cm2 16?3 cm2 4?3 cm2 21.3 cm2 64 cm2 16?3 cm2 4?3 cm2 21.3 cm2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Req. Area = ?3/4 x a2 = ?3/4 x 82 cm2= 16?3 cm2
Area Problems The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle? None of these Data inadequate 18 cm 24 cm None of these Data inadequate 18 cm 24 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2(l + b) = 5 b 1 ⟹ 2l + 2b = 5b ⟹ 3b = 2l b = 2 l 3 Then, Area = 216 cm2 ⟹ l x b = 216 ⟹l x 2 l = 216 3 ⟹ l2 = 324 ⟹ l = 18 cm
Area Problems The radius of a circular field is 25 m. Find the area of the field. 135 ? sq m 25 ? sq m 625 ? sq m 125 ? sq m 135 ? sq m 25 ? sq m 625 ? sq m 125 ? sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = ?r2 = ? x 25 x 25 = 625? sq m.
Area Problems The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres? 120 None of these Data inadequate 40 120 None of these Data inadequate 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m
EXAMIANS