Electrical Machines If the excitation is reduced, the power factor is None of these unity power factor leading power factor lagging power factor None of these unity power factor leading power factor lagging power factor ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Current in a coil undergoing commutation is not able to get reversed completely by the end of commutation period. It is due to reactance voltage induced in the coil. coil resistance. None of these armature emf. reactance voltage induced in the coil. coil resistance. None of these armature emf. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines For a standard frequency the machine operates at a particular speed known as normal speed. any of the above. slip speed. synchronous speed. normal speed. any of the above. slip speed. synchronous speed. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A shunt generator has a critical field resistance of 300 Ω at a speed of 800 rpm if the speed is raised to 1000 rpm the critical field resistance is 150 Ω. 225 Ω. 145 Ω. 375 Ω. 150 Ω. 225 Ω. 145 Ω. 375 Ω. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A separately excited DC motor has an armature resistance of 0.5 Ohm. The supply voltage is 250V. Armature current is 20A and the speed of rotation is 1500 rpm. Find the torque developed? 15.6 Nm 16.55 Nm 15.28 Nm Zero 15.6 Nm 16.55 Nm 15.28 Nm Zero ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a 3 - Φ IM with line frequency f1 and winding factor kw1 and kw2 for stator and rotor respectively the ratio of per phase stator winding emf E1 to per phase rotor winding emf E2 at standstill is given by E1 / E2 = N1 / N2. E1 / E2 = 1. E1 / E2 = N1kw1 / N2kw2. E1 / E2 = f1kw1 / f2kw2. E1 / E2 = N1 / N2. E1 / E2 = 1. E1 / E2 = N1kw1 / N2kw2. E1 / E2 = f1kw1 / f2kw2. ANSWER DOWNLOAD EXAMIANS APP
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