Refrigeration and Air Conditioning If the evaporator temperature of a plant is lowered, keeping the condenser temperature constant, the h.p. of compressor required will be More More/less depending on rating Same Less More More/less depending on rating Same Less ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The ratio of actual mass of water vapour in a given volume of moist air to the mass of water vapour in the same volume of saturated air at the same temperature and pressure, is called Degree of saturation Relative humidity Absolute humidity Humidity ratio Degree of saturation Relative humidity Absolute humidity Humidity ratio ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning Formation of frost on evaporator in refrigerator Can be avoided by proper design Is immaterial Increases heat transfer rate Results in loss of heat due to poor heat transfer Can be avoided by proper design Is immaterial Increases heat transfer rate Results in loss of heat due to poor heat transfer ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The temperature of air recorded by a thermometer, when it is not affected by the moisture present in the air, is called Dew point temperature Dry bulb temperature Wet bulb temperature None of these Dew point temperature Dry bulb temperature Wet bulb temperature None of these ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning Dry bulb temperature is the temperature of air recorded by a thermometer, when Its bulb is surrounded by a wet cloth exposed to the air The moisture present in it begins to condense It is not affected by the moisture present in the air None of the listed here Its bulb is surrounded by a wet cloth exposed to the air The moisture present in it begins to condense It is not affected by the moisture present in the air None of the listed here ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning A refrigerating system operating on reversed Brayton refrigeration cycle is used for maintaining 250 K. If the temperature at the end of constant pressure cooling is 300 K and rise in the temperature of air in the refrigerator is 50 K, then the net work of compression will be (assume air as working substance with Cp = 1 kJ/kg) 125 kJ/kg 25 kJ/kg 50 kJ/kg 100 kJ/kg 125 kJ/kg 25 kJ/kg 50 kJ/kg 100 kJ/kg ANSWER DOWNLOAD EXAMIANS APP
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