Theory of Structures If Q is load factor, S is shape factor and F is factor of safety in elastic design, the following: Q = S + F Q = S × F Q = F – S Q = S – F Q = S + F Q = S × F Q = F – S Q = S – F ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A close coil helical spring of mean diameter D consists of n coils of diameter d. If it carries an axial load W, the energy stored in the spring, is 4W²Dn/d4N 4W²D3n²/d4N 4W²D3n/d4N 4WD²n/d4N 4W²Dn/d4N 4W²D3n²/d4N 4W²D3n/d4N 4WD²n/d4N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then M/I = E/R = F/Y M/I = E/R = Y/F I/M = R/E = F/Y M/I = R/E = F/Y M/I = E/R = F/Y M/I = E/R = Y/F I/M = R/E = F/Y M/I = R/E = F/Y ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures At yield point of a test piece, the material Behaves in an elastic manner Undergoes plastic deformation Obeys Hooke’s law Regains its original shape on removal of the load Behaves in an elastic manner Undergoes plastic deformation Obeys Hooke’s law Regains its original shape on removal of the load ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel rod of sectional area 250 sq. mm connects two parallel walls 5 m apart. The nuts at the ends were tightened when the rod was heated to 100°C. If steel = 0.000012/C°, Esteel = 0.2 MN/mm², the tensile force developed at a temperature of 50°C, is 80 N/mm² 150 N/mm² 100 N/mm 2 120 N/mm² 80 N/mm² 150 N/mm² 100 N/mm 2 120 N/mm² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A spring of mean radius 40 mm contains 8 action coils of steel (N = 80000 N/mm²), 4 mm in diameter. The clearance between the coils being 1 mm when unloaded, the minimum compressive load to remove the clearance, is 35 N 25 N 40 N 30 N 35 N 25 N 40 N 30 N ANSWER DOWNLOAD EXAMIANS APP