Electrical Machines If iron loss and full load copper loss of any transformer are denoted by Pi and Pc, then the load corresponding to maximum efficiency is given by (Pi / Pc)1.6 × full Load. (Pi / Pc)0.5 × Full Load. (Pi / Pc) × full Load. (Pi / Pc)2 × full Load. (Pi / Pc)1.6 × full Load. (Pi / Pc)0.5 × Full Load. (Pi / Pc) × full Load. (Pi / Pc)2 × full Load. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In case of a compensated DC series motor, the compensating winding is provided In parallel with the armature winding. In series with the armature winding. In parallel with the field winding. As a separate unit. In parallel with the armature winding. In series with the armature winding. In parallel with the field winding. As a separate unit. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The current drawn by a 220 V DC series motor of armature resistance 0.5Ω and back back emf 200 V is 44 A. 40 A. 400 A. 440 A. 44 A. 40 A. 400 A. 440 A. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 220 V DC machine has an armature resistance 1 Ω. If the full load current is 20 A, the difference of induced voltage between generator and motor is 40 V. 0 V. 60 V. 20 V. 40 V. 0 V. 60 V. 20 V. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Which of the following motors has low ratings only? Capacitor start Resistance split phase Shaded pole Capacitor run Capacitor start Resistance split phase Shaded pole Capacitor run ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A short circuit test on a transformer gives copper loss at any load. copper loss at half load. copper loss at full load. copper loss at over load. copper loss at any load. copper loss at half load. copper loss at full load. copper loss at over load. ANSWER DOWNLOAD EXAMIANS APP
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