Fractions and Decimals If √5 = 2.24, then the value of 3√5 / 2√5 - 0.48 is ? 168 1.68 16.8 None of these 168 1.68 16.8 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = 3√5 / 2√5 - 0.48= (3 x 2.24) / (2 x 2.24) - 0.48= 6.72 / 4.48 - 0.48 = 6.72 / 4 = 1.68
Fractions and Decimals 3 / [ 3+ {(0.3 - 3.03) / (3 x 0.91)}] = ? 2.0 0.5 1.5 1.0 2.0 0.5 1.5 1.0 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = 3 / [ 3+ {(0.3 - 3.03) / (3 x 0.91)}] = 3 / [3- { 273 / (3 x 91)}] = 3 / (3-1)= 3 / 2 = 1.5
Fractions and Decimals If 1.5x = 0.04y, then the value of ( (y - x) / (y+x) ) is : 61/63 73/77 65/67 71/74 61/63 73/77 65/67 71/74 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP x / y = 0.04 / 1.5 = 4 / 150 = 2 / 75.= > ( (y - x) / (y+x) ) = (1 - (x / y)) / ( 1 + ( x / y)) = (1 - 2/75) / (1 + 2/75) = 73/77.
Fractions and Decimals 8.32 x 0.999 = ? 8.31168 831.168 8311.68 83.1168 8.31168 831.168 8311.68 83.1168 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = 8.32 x 0.999= 8.32 x (1-0.001) = 8.32 - 8.32 x 0.001=8.32 - .00832 = 8.31168
Fractions and Decimals (0.2 * 0.2 + 0.01) ( 0.1 * 0.1 + 0.02)^(-1) is equal to : 4/3 7/3 5/3 6/3 4/3 7/3 5/3 6/3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given = (0.2 * 0.2 + 0.01) / ( 0.1 * 0.1 + 0.02)= (0.04 + 0.01) / (0.01 + 0.02) = 0.05 / 0.03= 5/3...
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2013 2011 2012 2014 2013 2011 2012 2014 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
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