Mass Transfer Henry's law states that the Partial pressure of a component over a solution is proportional to its mole fraction in the liquid Vapour pressure is equal to the product of the mole fraction and total pressure Partial pressure of a component over a solution is proportional to the mole fraction in the vapour Partial pressure is equal to the product of the mole fraction and total pressure Partial pressure of a component over a solution is proportional to its mole fraction in the liquid Vapour pressure is equal to the product of the mole fraction and total pressure Partial pressure of a component over a solution is proportional to the mole fraction in the vapour Partial pressure is equal to the product of the mole fraction and total pressure ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Humidity chart is useful for the solution of problems concerning condensation, vaporisation and air conditioning. At a given dry bulb temperature, value of humidity obtained from the humidity chart directly, is in terms of __________ humidity. Relative Molal Percentage None of these Relative Molal Percentage None of these ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Mass transfer co-efficient 'K' according to penetration theory varies with mass dif-fusivity as D1.5 D0.5 1/D D D1.5 D0.5 1/D D ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Penetration theory states that the mass transfer co-coefficient is equal to (where, De is diffusivity and 't' is time) (4De/πt)1/2 (De.t)1/2 (4De/t) (De/t)1/2 (4De/πt)1/2 (De.t)1/2 (4De/t) (De/t)1/2 ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer An air-water vapour mixture has a dry bulb temperature of 60°C and a dew point temperature of 40°C. The total pressure is 101.3 kPa and the vapour pressure of water at 40°C and 60°C are 7.30 kPa and 19.91 kPa respectively.The humidity of air sample expressed as kg of water vapour/kg of dry air is 0.048 0.122 0.079 0.152 0.048 0.122 0.079 0.152 ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer The absorption factor is defined as (where, L = liquid flow rate, G = gas flow rate and, m = slope of the equilibrium line) LG/m G/mL ML/G L/mG LG/m G/mL ML/G L/mG ANSWER DOWNLOAD EXAMIANS APP