Applied Mechanics and Graphic Statics From the circular plate of a diameter 6 cm is cut out a circular plate whose diameter is equal to radius of the plate. The C.G. of the remainder shifts from the original position through 0.50 cm 0.75 cm 1.00 cm 0.25 cm 0.50 cm 0.75 cm 1.00 cm 0.25 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A satellite moves in its orbit around the earth due to None of these Gravitational force Centripetal force Centrifugal force None of these Gravitational force Centripetal force Centrifugal force ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The moment of inertia of a circular lamina of diameter ‘d’, about an axis perpendicular to the plane of the lamina and passing through its centre, is πd⁴/32 πd⁴/16 π/64 (D⁴ + d⁴) πd⁴/24 πd⁴/32 πd⁴/16 π/64 (D⁴ + d⁴) πd⁴/24 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two forces are in equilibrium, then the forces must (i) Be equal in magnitude (ii) Be opposite in sense (iii) Act along the same line (i) and (ii) All (i), (ii) and (iii) Only (i) (i) and (iii) (i) and (ii) All (i), (ii) and (iii) Only (i) (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals Q sin θ/P + Q sin θ P sin θ/P - Q cos θ Q sin θ/P + Q cos θ P sin θ/P + Q tan θ Q sin θ/P + Q sin θ P sin θ/P - Q cos θ Q sin θ/P + Q cos θ P sin θ/P + Q tan θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The graphical method of determining the forces in the members of a truss is based on Method of section Method of joint Either method None of the two methods Method of section Method of joint Either method None of the two methods ANSWER DOWNLOAD EXAMIANS APP
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