Machine Design For unequal width of butt straps, the thicknesses of butt straps are 0.75 t for narrow strap on the inside and 0.625 t for wide strap on the outside 0.75 t for wide strap on the inside and 0.625 t for narrow strap on the outside 0.75 t for both the straps on the inside and outside 0.625 t for both the straps on the inside and outside 0.75 t for narrow strap on the inside and 0.625 t for wide strap on the outside 0.75 t for wide strap on the inside and 0.625 t for narrow strap on the outside 0.75 t for both the straps on the inside and outside 0.625 t for both the straps on the inside and outside ANSWER DOWNLOAD EXAMIANS APP
Machine Design When the shaft rotates in anticlockwise direction at high speed in a bearing, it will Move towards right of the bearing making metal to metal contact Move towards left of the bearing making metal to metal contact Move towards right of the bearing making no metal to metal contact Have contact at the bottom most of the bearing Move towards right of the bearing making metal to metal contact Move towards left of the bearing making metal to metal contact Move towards right of the bearing making no metal to metal contact Have contact at the bottom most of the bearing ANSWER DOWNLOAD EXAMIANS APP
Machine Design In hydrostatic bearings Do not require external supply of lubricant The Oil film pressure is generated only by the rotation of the journal The oil film is maintained by supplying oil under pressure Grease is used for lubrication Do not require external supply of lubricant The Oil film pressure is generated only by the rotation of the journal The oil film is maintained by supplying oil under pressure Grease is used for lubrication ANSWER DOWNLOAD EXAMIANS APP
Machine Design The taper on a rectangular sunk key is 1 in 32 1 in 100 1 in 48 1 in 16 1 in 32 1 in 100 1 in 48 1 in 16 ANSWER DOWNLOAD EXAMIANS APP
Machine Design In order to ensure self locking in a screw jack, it is essential that helix angle is __________ friction angle. Larger than None of these Smaller than Equal to Larger than None of these Smaller than Equal to ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
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