Irrigation Engineering For diversion of flood water of rivers, the type of canal constructed, is Inundation canal Perennial canal Ridge canal Canal Inundation canal Perennial canal Ridge canal Canal ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering The stream which does not have any base flow contribution is called perennial stream ephemeral stream None of these intermittent stream perennial stream ephemeral stream None of these intermittent stream ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering A runoff river plant is None of these a high head scheme a low head scheme a medium head scheme None of these a high head scheme a low head scheme a medium head scheme ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering The uplift pressure on a dam can be controlled by i) constructing cutoff under upstream face ii) constructing drainage channels bet-ween the dam and its foundation iii) by pressure grouting in foundation The corret answer is both (i) and (iii) only (i) (i), (ii) and (iii) both (i) and (ii) both (i) and (iii) only (i) (i), (ii) and (iii) both (i) and (ii) ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering If B and d are the bed width and depth of a channel in meters, the combined losses due to evaporation and seepage in cumecs per kilometer length of the channel, is (1/50) × (B + d)2/3 (1/150) × (B + d)2/3 (1/200) × (B + d)2/3 (1/100) × (B + d)2/3 (1/50) × (B + d)2/3 (1/150) × (B + d)2/3 (1/200) × (B + d)2/3 (1/100) × (B + d)2/3 ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering Fundamental momentum equation for a hydraulic jump, is D₂² - D₁² = (2q/g) × (V - V₂) D₁² + D₂² = (2q/g) × (V₂ - V₁) D₁² - D₂² = (2q/g) × (V₁ - V₂) D₁² - D₂² = (2q/g) × (V₂ - V₁) D₂² - D₁² = (2q/g) × (V - V₂) D₁² + D₂² = (2q/g) × (V₂ - V₁) D₁² - D₂² = (2q/g) × (V₁ - V₂) D₁² - D₂² = (2q/g) × (V₂ - V₁) ANSWER DOWNLOAD EXAMIANS APP
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